2 years ago

The length of a rectangle plus its width is 24 cm. The area is 135 cm. What are the length and width of the rectangle

Mathematics

1 answer:

lilavasa [31]2 years ago

6 0

Answer:

$l = 5.63 \\$

hope this helps

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An observer (0) is located 400 feet from a building (B). The observer notices a kite (K) flying at a 29° angle of

Katyanochek1 [597]

Answer:

$\tan(29) = \frac{h}{400} \\ h = 400 \tan(29) \\ h = 221.724 \: ft$

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3 years ago

Can someone help, no links plz

AfilCa [17]

Answer:

x=19.4

Step-by-step explanation:

a^2+b^2=c^2

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3 years ago

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Consider M, N, and P. collinear points on MP.

Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}$

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}$

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}$