1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lera25 [3.4K]
3 years ago
13

Sara reads 250 words per minute for 2 hours and gets tired and reads 125 words per minute for 3 hours. on average how many words

per minute does Sara read?
Mathematics
1 answer:
brilliants [131]3 years ago
5 0
<span>250*(2*60)=30000
125*(3*60)=22500
22500+30000=52500
52500:((3+2)*60)=175 (</span><span>words per minute)</span>
You might be interested in
What is 6.16×10*6 in standard form?
Paladinen [302]

Answer:

6.16×10*6

Step

6=2+_AT ERATLION

Question

What is in standard form?-by-step explanation:

8 0
3 years ago
PLZ HELP I WILL MARK BRAINLIEST <br> Use the given values to complete each table
Ne4ueva [31]
Ok this is a pretty easy one.
2=22
3=20
4=18
6 0
3 years ago
Read 2 more answers
What is the lcm of 56 and 136
Citrus2011 [14]

Answer:

LCM(56,136)=952

Step-by-step explanation:

To find the LCM of two numbers, factorize both these numbers:

56=2\cdot 28=2\cdot 2\cdot 14=2\cdot 2\cdot 2\cdot 7=2^3\cdot 7\\ \\136=2\cdot 68=2\cdot 2\cdot 34=2\cdot 2\cdot 2\cdot 17=2^3\cdot 17

These two numbers have the common factor of 2^3.

Now multiply this common factor by the remaining factors:

LCM(56,136)=2^3 \cdot 7\cdot 17=952

Therefore, the LCM is 952.

8 0
3 years ago
Which of the following is equivalent to 140 centiliters?
Norma-Jean [14]
The answer is C) because one litre=100 centiliters, and one kilolitre=one litre which means that one kilolitre =100000 centiliters
So 140 centiliters are 140 divided by 100000 kiloliters=0.00140 kiloliters
6 0
3 years ago
Read 2 more answers
The local oil changing business is very busy on Saturday mornings and is considering expanding. A national study of similar busi
eimsori [14]

Answer:

t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131  

Rejection Zone: t_{calculated} or t_{calculated}>2.131

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=4.2 represent the sample mean  

s=1.4 represent the sample standard deviation  

n=16 represent the sample selected  

\alpha=0.05 significance level  

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is different from 3.6, the system of hypothesis would be:    

Null hypothesis:\mu = 3.6    

Alternative hypothesis:\mu \neq 3.6    

If we analyze the size for the sample is < 30 and we know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714

Critical values

On this case since we have a bilateral test we need to critical values. We need to use the t distribution with df=n-1=16-1=15 degrees of freedom. The value for \alpha=0.05 and \alpha/2=0.025 so we need to find on the t distribution with 15 degrees of freedom two values that accumulates 0.025 of the ara on each tail. We can use the following excel codes:

"=T.INV(0.025,15)" "=T.INV(1-0.025,15)"

And we got t_{crit}=\pm 2.131    

So the decision on this case would be:

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131  

Rejection Zone: t_{calculated} or t_{calculated}>2.131

Conclusion    

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

3 0
3 years ago
Other questions:
  • Solve this problem out
    13·1 answer
  • Steve bought a 15-pound bag of concrete. He spilled the bag into smaller bags that each holds 2 1/2 pounds. How many smaller bag
    14·1 answer
  • This partial circle has a radius of 11 inches.
    7·1 answer
  • -PLEASE HURRY- this is the third time I’ve asked this question and no one has given me an answer.
    11·1 answer
  • To convert a temperature in degrees celsius to degrees fahrenheit multiply the celsius temperature by 9/5 and then add 32° is th
    7·1 answer
  • Someone please help me quick, I don't know the answer to this question
    8·2 answers
  • Construct a square with sides each 6.5cm long
    13·2 answers
  • Identify the polynomial.
    15·2 answers
  • Which of the equations matches the line shown in the diagram?
    5·1 answer
  • Given p = 3k + 8, express k in terms of p.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!