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levacccp [35]
2 years ago
10

Billy graphed the system of linear equations to find an approximate solution.

Mathematics
1 answer:
jeka57 [31]2 years ago
6 0

The points that are possible approximations for this system are; (2.2, -1.4) and (2.2, -1.35)

<h3>How to find the solution of a linear graph?</h3>

We are given the equations of the linear graphs as;

y = ⁷/₄x + ⁵/₂

y = ³/₄x - 3

Notice that the lines intersect each other and by definition, if the lines of the system of equations intersect, then the system has one solution. This means that the point of intersection of the lines is the solution of the system. It can be written as:

(x, y)

x is the x-coordinate .

y is the y-coordinate.

In this case, we can identify that:

- the x-coordinate of the point of intersection is between; x = 2 and x = 3

- The y-coordinate of the point of intersection is between y = -1 and y = -2

Based on the above, we can conclude that the points that are possible approximations for this system are; (2.2, -1.4) and (2.2, -1.35)

Read more about Linear Graph Solution at; brainly.com/question/14323743

#SPJ1

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Step-by-step explanation:

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The surface area and volume of a sphere are in the ratio of 3:7cm.What is the circumference of its great circle and volume​
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Answer:

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∴V:S=1:3 cm

Step-by-step explanation:

Hope this helps. If any questions, please ask in comments.

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2 years ago
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8 0
3 years ago
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igor_vitrenko [27]

Answer:

3

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8 0
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A bank loaned out $21,500 , part of it at the rate of 11% annual interest, and the rest at 10% annual interest. The total intere
Luda [366]

Answer:

The loaned amount at 11 % is $ 19,000

The loaned amount at 10 % is $ 2,500

Step-by-step explanation:

Given as :

The total loan amount = $21,500

The total interest earn = $2,340.00

The rate of interest are 11 %  and 10 %

Let The loan amount at 11 % rate = $P

and The loan amount at 10 % rate = $21,500 - $P

Let The loan took for 1 year

Now,<u> From Simple Interest method </u>

Simple Interest = \dfrac{\textrm Principal\times \textrm Rate\times \textrm Time}{100}

SI_1 = \dfrac{P_1\times R_1\times \textrm Time}{100}

Or, SI_1 = \dfrac{P\times 11\times \textrm 1}{100}

Similarly

SI_2 = \dfrac{21,500 - P\times 10\times \textrm 1}{100}

∵  SI_1 +  SI_2 =  $2,340

Or, \dfrac{P\times 11\times \textrm 1}{100} + \dfrac{21,500 - P\times 10\times \textrm 1}{100} = $2,340

Or, 11 P - 10 P + 215000 = 234000

Or, P = 234000 - 215000

∴ P = $ 19,000

And $21,500 - $ 19,000 = $ 2,500

Hence The loaned amount at 11 % is $ 19,000

And     The loaned amount at 10 % is $ 2,500    Answer

8 0
3 years ago
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