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3 years ago

21,000 round to the nearest thousand

Mathematics

2 answers:

exis [7]3 years ago

7 0

21,000 rounded to the nearest thousand will be 20,000

vekshin13 years ago

3 0

It is already rounded to the nearest 1000. The answer is 21,000.

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Becca hit 7 more homes run than beverely becca hit 21home runs. How many home runs did beverly hit

ZanzabumX [31]

Beverly hit 14 home runs because 7 minus 21 is 14

8 0

4 years ago

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Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

tankabanditka [31]

Answer:

Slope of a tangent to the curve = $f'(x) = \frac{-1 }{(x+1)^{2} }$

Step-by-step explanation:

Given - y = 1/x+1

To find - Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

Proof -

We know that,

Slope of tangent line = f'(x) = $\lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$

We have,

f(x) = y = $\frac{1}{x+1}$

So,

f(x+h) = $\frac{1}{x+h+1}$

Now,

Slope = f'(x)

And

$f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \\= \lim_{h \to 0} \frac{\frac{1}{x+h+1} - \frac{1}{x+1} }{h}\\= \lim_{h \to 0} \frac{x+1 - (x+h+1) }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{x +1 - x-h-1 }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-h }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-1 }{(x+1)(x+h+1)}\\= \frac{-1 }{(x+1)(x+0+1)}\\= \frac{-1 }{(x+1)(x+1)}\\= \frac{-1 }{(x+1)^{2} }$

∴ we get

Slope of a tangent to the curve = $f'(x) = \frac{-1 }{(x+1)^{2} }$

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3 years ago

What’s 5000÷4x8÷3x20?

PilotLPTM [1.2K]

Answer:

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Step-by-step explanation:

5000

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3 years ago

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What is 3.276 x 10^9 in standard form?

Delicious77 [7]

The exponent is a positive number, so you move the decimal point, that many places to the right:

3.276 x 10^9 = 3,276,000,000

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3 years ago

What fraction of a circle does an arc measure of 30 degrees encompass?

Naddika [18.5K]

Answer:

$\frac{1}{12}$

Step-by-step explanation:

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**This content involves simplifying fractions and knowledge on the angle sum of a circle which you may wish to revise. I'm always happy to help!

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3 years ago