Answer:
I think there is a mistake somwhere . Please can someone else try it out
Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer:
C
Step-by-step explanation:
So its 12 divided by 1/5 so
12 x 1= 12
1 x 5= 5
That is 12 over 5 and u will divide the numerator by the denominator to get 2.4
Dont know if thts exactly right bcuz its been a while since i learned this but i hope it helps
