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3 years ago

Question 16 (1 point) Solve the inequality −3(r−5)+7≥28. Question 16 options: r≤−2 r≥−2 r≤−283 r≤−12

Mathematics

2 answers:

zhannawk [14.2K]3 years ago

8 0

Answer:

Step-by-step explanation:

-39r-5=>

Anuta_ua [19.1K]3 years ago

5 0

Answer:

Step-by-step explanation:

-3(r - 5) + 7 > = 28

-3r + 15 + 7 > = 28

-3r + 22 > = 28

-3r > = 28 - 22

-3r > = 6

r < = -6/3

r < = -2 (thats less then or equal)....I had to switch the sign because I divided by a negative

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Alex17521 [72]

Answer:

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3 years ago

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MariettaO [177]

Answer:

$X_1 = 1000000 , P(X_1)= 0.0000005$

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And then replacing we have this for the expected value:

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And after do the math we got:

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Step-by-step explanation:

For this case we can define the random variable X as the amount that we can win. We can find the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And we have the following probabilities and possible values given:

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$X_2 = 200000 , P(X_2)= 0.000002$

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And then replacing we have this for the expected value:

$E(X) = 1000000*0.0000005 +200000*0.000002+30000*0.00001 2*0.9999875$

And after do the math we got:

$E(X) = -0.79998$

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