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2 years ago

Which is not an example of interdependent parties

SAT

1 answer:

suter [353]2 years ago

7 0

The man giving a talk at the library on plants is not an example of interdependent parties.

<h3 /><h3>What are interdependent parties?</h3>

This is the term that is used to refer to the relationship that is characterized by depending on other people.

This is the type of relationship that occurs due to the fact that people have to rely on others.

Read more on interdependence here; brainly.com/question/18251781

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A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin

Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

131.6 N/C

12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

$\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}$

Which gives;

$\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C$

$\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C$

Which gives;

$\vec{E}_1 = \mathbf{21.6 \, N/C \cdot \hat x + 28.8 \, N/C \hat y}$

$\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C$

Therefore;

$\vec {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)$

$\vec {E} = \mathbf{\left( -128.4 \, N/C \right) \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)}$

The magnitude of the net electric field is therefore;

E = $\sqrt{(-128.4^2 + 28.8^2)}$ ≈ 131.6

The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>

(b) The direction of the net electric field at the origin.

$The \ direction \ is \ arctan \left(\dfrac{28.8}{-128.4} \right) \approx \underline{ 12.6^{\circ}} \ above \ the \ negative \ x-axis$

Learn more about electric field strength here:

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2 years ago

The students with the most exceptional financial need are eligible for the

Llana [10]

Answer:

(FSEGO)

Explanation:

7 0

3 years ago

In which grade do kids generally start to prepare for SAT exams?

harkovskaia [24]

We suggest starting to prep for the the SAT as early as eighth grade year. It sound early, but if a student plans on taking the SAT several times throughout high school, eighth graders can take a relaxed and long-view approach to prepping, and can plan on taking their first SAT sophomore year.

3 0

3 years ago

What is the name for the multiple multiverse?

serg [7]

I believe the name of the multiverse is called (InGeneralSchemasTheory)

6 0

4 years ago

Read 2 more answers

rock x is released from rest at the top of a cliff that is on earth. a short time later, rock y is released from rest from the s

Sergeu [11.5K]

The velocity of an object in free fall increases downwards with time

Please find attached the correct graph showing velocity as a function time, with the positive direction to be upwards.

Reason:

The known parameters are;

Location where the rocks are released; Earth

The time at which rock Y is released = A few seconds after rock X is released.

Required:

To select the graph that shows the vertical velocity of rock, <em>x</em>, as a function of time.

Solution:

Let <em>t </em>represent the time after which rock x are released, with the positive direction being upwards, we have;

The equation for the velocity of x is v = -9.81·t

With the above equation, the graph of the vertical velocity of rock x is plotted with MS Excel.

Learn more about the graphs of velocity of object in free fall here:

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4 0

2 years ago