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inysia [295]
2 years ago
7

You are given five integers and your task is to find the smallest of them

SAT
1 answer:
Vikentia [17]2 years ago
4 0

The minimum number of comparisons to find the smallest number from 5 integers is 4.

<h3>How to find the Smallest Integer?</h3>

Let the five numbers be a,b,c,d and e.

Let s be an integer

Comparison 1:

a and b will be compared first and the smaller number of them will be equal to s

Comparison 2:

Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.

Comparison 3:

Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison

Comparison 4:

Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.

After 4th comparison, s will be equal to smallest number of 5 integers.

Thus;

Total comparisons = 4

Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.

Read more about Smallest Integer at; brainly.com/question/13329614

#SPJ1

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Based on the standard formula and data in the question, the frequency of a sound source that produces the same wavelength in 20∘c air is "<u>115.87Hz</u>."

<h3>What is the frequency of a sound source?</h3>

The <u>frequency of a sound source</u> is the quantity of waves that move through a point per unit of time.

Typically, a sound wave arises from a source vibrating at a frequency f, propagates at v, and has a wavelength λ.

Therefore, in this case, we have

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Frequency (f) =?

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Hence, in this case, it is concluded that the correct answer is 115.87Hz.

Learn more about Frequency of Sound Source here: brainly.com/question/1418576

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