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amm1812
3 years ago
12

0.23 or 2.3% which is greater?

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

0.23

Step-by-step explanation:

2.3% = 0.023

So 0.23*100=23% therefore larger than 2.3%


Any questions feel free to ask. Thanks

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From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
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Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

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Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

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