1. Answer:
30 is your frequency
Step-by-step explanation:
Frequency in this case would be the number of winners. So to find the frequency we would need to add up the total number of winners in the histogram.
So, 0 + 2 + 5 + 6 + 8 + 5 + 4 = 30
2. Answer:
6 (you already put that)
3.
The median can be found in the 50-59 bin or interval.
<span>Dawn was at 6 am.
Variables
a = distance from a to passing point
b = distance from b to passing point
c = speed of hiker 1
d = speed of hiker 2
x = number of hours prior to noon when dawn is
The first hiker travels for x hours to cover distance a, and the 2nd hiker then takes 9 hours to cover that same distance. This can be expressed as
a = cx = 9d
cx = 9d
x = 9d/c
The second hiker travels for x hours to cover distance b, and the 1st hiker then takes 4 hours to cover than same distance. Expressed as
b = dx = 4c
dx = 4c
x = 4c/d
We now have two expressions for x, set them equal to each other.
9d/c = 4c/d
Multiply both sides by d
9d^2/c = 4c
Divide both sides by c
9d^2/c^2 = 4
Interesting... Both sides are exact squares. Take the square root of both sides
3d/c = 2
d/c = 2/3
We now know the ratio of the speeds of the two hikers. Let's see what X is now.
x = 9d/c = 9*2/3 = 18/3 = 6
x = 4c/d = 4*3/2 = 12/2 = 6
Both expressions for x, claim x to be 6 hours. And 6 hours prior to noon is 6am.
We don't know the actual speeds of the two hikers, nor how far they actually walked. But we do know their relative speeds. And that's enough to figure out when dawn was.</span>
Answer:
Interpreting as: 10y+11=25-3y
Input:
10 y + 11 = 25 - 3 y
Slot method or permutations
top 3
6 for first slot
5 for 2nd slot
4 for 3rd
6*5*4=120
120 possiblites
answer is C
Answer:
the answer would be 9 I think
