Answer:
x= -4
Step-by-step explanation:
Step 1- Subtract 10 to both sides.
-5x+10< 30
<u> -10 -10</u>
-5x< 20
Step 2- Divide both sides by -5.
<u>-5x</u>< <u>20</u>
-5 -5
x= -4
<u>Check </u>
-5(-4)+10< 30
-20+10< 30
-10< 30
Hope this helps! :)
The brake horsepower of an engine that’s being tested is coupled to a dynamometer that has a radius arm of 1.70 feet is letter D. 170.
Answer:
Explanation:
What we need to do is to convert 
into a new - but still equal - fraction, one with a denominator of 3. In order to convert a fraction, you either divide or multiply both the denominator and the numerator by the same number.
We know that the answer has to be a fraction with the denominator of 3. Take a look at the denominator of - it's 12. Ask yourself: 12 divided by what number equals 3? That number would 4.
So, divide 8 by 4 as well and you would get 2. Therefore, the numerator would be 2 and the answer is .
For the first one write 9 divided by 2 gives your your radius an it’s 3.5. the formula is 2 x 3.14 x radius and that gives you 21.98.
the 2nd one is 2 x 3.14 x 9 = 56.52
the 3rd is 2 x 3.14 x 5= 31.4
formula is always 2 x 3.14 (or pie) x radius
to get your radius from your diameter you do your diameter divided by 2
The formula of a volume of a sphere:
R - radius
We have the volume = 288 in³. Substitute:
![\dfrac{4}{3}\pi R^3=288\qquad\text{multiply both sides by 3}\\\\4\pi R^3=864\qquad\text{divide both sides by}\ 4\pi\\\\R^3=\dfrac{216}{\pi}\to R=\sqrt[3]{\dfrac{216}{\pi}}\\\\R=\dfrac{\sqrt[3]{216}}{\sqrt[3]{\pi}}\\\\R=\dfrac{6}{\sqrt[3]{\pi}}\ in](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20R%5E3%3D288%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%203%7D%5C%5C%5C%5C4%5Cpi%20R%5E3%3D864%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%7D%5C%204%5Cpi%5C%5C%5C%5CR%5E3%3D%5Cdfrac%7B216%7D%7B%5Cpi%7D%5Cto%20R%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B216%7D%7B%5Cpi%7D%7D%5C%5C%5C%5CR%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B216%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%5C%5C%5C%5CR%3D%5Cdfrac%7B6%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%5C%20in)
The formula of a surface area of a sphere:
Substitute:
![S.A.=4\pi\left(\dfrac{6}{\sqrt[3]{\pi}}\right)^2=4\pi\cdot\dfrac{6^2}{\sqrt[3]{\pi^2}}=\dfrac{4\pi\cdot36}{\sqrt[3]{\pi^2}}=\dfrac{144\pi}{\sqrt[3]{\pi^2}}\\\\S.A.=\dfrac{144\pi}{\sqrt[3]{\pi^2}}\cdot\dfrac{\sqrt[3]{\pi}}{\sqrt[3]{\pi}}=\dfrac{144\pi\sqrt[3]{\pi}}{\sqrt[3]{\pi^3}}=\dfrac{144\pi\sqrt[3]{\pi}}{\pi}=\boxed{144\sqrt[3]{\pi}\ in^2}](https://tex.z-dn.net/?f=S.A.%3D4%5Cpi%5Cleft%28%5Cdfrac%7B6%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%5Cright%29%5E2%3D4%5Cpi%5Ccdot%5Cdfrac%7B6%5E2%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E2%7D%7D%3D%5Cdfrac%7B4%5Cpi%5Ccdot36%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E2%7D%7D%3D%5Cdfrac%7B144%5Cpi%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E2%7D%7D%5C%5C%5C%5CS.A.%3D%5Cdfrac%7B144%5Cpi%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E2%7D%7D%5Ccdot%5Cdfrac%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%3D%5Cdfrac%7B144%5Cpi%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cpi%5E3%7D%7D%3D%5Cdfrac%7B144%5Cpi%5Csqrt%5B3%5D%7B%5Cpi%7D%7D%7B%5Cpi%7D%3D%5Cboxed%7B144%5Csqrt%5B3%5D%7B%5Cpi%7D%5C%20in%5E2%7D)
