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Ray Of Light [21]
3 years ago
12

An engine that’s being tested is coupled to a dynamometer that has a radius arm of 1.70 feet. The test data shows a speed of 5,0

00 rpm and a load of 100 pounds. What’s the brake horsepower? A. 162 B. 161 C. 129 D. 170
Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
7 0
The brake horsepower of an engine that’s being tested is coupled to a dynamometer that has a radius arm of 1.70 feet is letter D. 170.
Rudik [331]3 years ago
5 0
162 is probably the answer.

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Which table shows a proportional relationship between x and y?
oksano4ka [1.4K]
The top one. Think about the difference between each one: X goes from 1 to 2 and Y goes from 5 to 10. Each number you go up, Y increases by 5. This means there is a proportional relationship.
6 0
2 years ago
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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
2 years ago
What is the ratio of 420m to 1 km
suter [353]

Answer:

21/50 or 21:50

Step-by-step explanation:

1km = 1000m

That means one meter is equal to 1/1000 of a km.

420 meters is 420/1000 of a km which is equal to 42/100 = 21/50 or 21:50

Is it right?

Also can I have Brainiest

7 0
3 years ago
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Convert -18° to radians.
aev [14]
The answer is 0.314 radian
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3 years ago
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What is the area of the parallelogram?
Marizza181 [45]

Answer:

0.6

Step-by-step explanation:

3 0
3 years ago
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