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skad [1K]
2 years ago
7

Add. −4+(−19) Enter your answer in the box. help please!

Mathematics
2 answers:
olga2289 [7]2 years ago
8 0

Answer:

-23

Step-by-step explanation:

-4+(-19)

= -4-19

= -23

77julia77 [94]2 years ago
7 0

Answer:

-4+(-19)

open the bracket

 (+)×(-) = -

-4-19= -23

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Answer quick please!
astra-53 [7]

Answer:

25%

Step-by-step explanation:

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3 years ago
Which method can be used to find the interquartile range for a set of data ?
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The interquartile range (IQR) can be found by finding the difference of the upper and lower quartiles
6 0
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5 0
3 years ago
The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)

\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

6 0
3 years ago
-45=5y<br>I need the answer​
slamgirl [31]

Answer:

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Step-by-step explanation:

-45=5y

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5 0
3 years ago
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