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adelina 88 [10]
2 years ago
15

What is the slope of this line A -1/2 B 1/2 C 2​

Mathematics
1 answer:
denpristay [2]2 years ago
4 0
-1/2 is your answer to this question
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The height of a triangle is half the length of its base. The area of the triangle is 12.25cm. Find the height
pentagon [3]
Answer:  The height of the triangle is:  " 3.5 cm " .
_______________________________________________________
<u>
Note</u>:
 The formula/equation for the area, "A" , of a triangle is:

           A = (1/2) * b * h  ;  or write as:  A = (b * h) / 2 ; 
_________________________________________________
 in which:   "A = area of the triangle" ; 
                  "b = base length" ; 
                  "h = "[perpendicular] height" ; 
_________________________________________________
     Given:  h = (b/2) ;
                  A = 12.25 cm²
{Note:  Let us assume that the given area was "12.25 cm² " .}. 
_________________________________________________
 We are to find the height, "h" ; 

The formula for the Area, "A", is:   A = (b * h) / 2 ; 

Let us rearrange the formula ;
 to isolate the "h" (height) on one side of the equation; 

→ Multiply EACH side of the equation by "2" ; to eliminate the "fraction" ; 

2*A = [ (b * h) / 2 ] * 2 ; 

   to get:   " 2A = b * h " ; 

↔    " b * h = 2A " ; 

Divide EACH SIDE of the equation by "b" ; to isolate "h" on one side of the equation: 

        →  (b * h) / b  = (2A) / b ; 

to get: 
  
        →   h  =  2A / b ; 

Since  "h = b/2" ; subtitute "b/2" for "h" ; 
 
Plug in:  "12.25 cm² " for "A" ;

       →  b/2  =  2A/b ;   →  Note:  " 2A/b = [2* (12.25 cm²) ] / b " ;

Note:  " 2* (12.25 cm²) = 24.5 cm² ; 

Rewrite as: 

       →  b/2  =  (24.5 cm²) / b ;
_____________________________________
Cross-multiply:   b*b = (24.5 cm²) *2 ; 

to get:   b² = 49 cm² ; 

Take the "positive square root" of each side of the equation" ; 
            to isolate "b" on one side of the equation ; & to solve for "b" ; 

             →  +√(b²)  =  +√(49 cm²) ; 

             →  b = 7 cm ; 

Now, we want to solve for "h" (the height) :
_________________________________________________________
             →  h = b / 2 = 7 cm / 2 = 3.5 cm ; 
_________________________________________________________
Answer:  The height of the triangle is:  " 3.5 cm <span>" .
</span>_________________________________________________________
6 0
3 years ago
Find the zeros (roots, x-intercepts) for each po<br> 3. f(x) = 5x^3- 20x
Aliun [14]

Answer:

v211

Step-by-step explanation:

6 0
3 years ago
Anyone know the answer to this algebra problem?
ikadub [295]

Answer:  \bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}

<u>Step-by-step explanation:</u>

\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}

\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}

3 0
3 years ago
Help question 4 pleaseeeeeeee
KIM [24]
The anwser is D and I’m sure of it
6 0
3 years ago
Read 2 more answers
Please help Find: ∠x ∠a ∠b
V125BC [204]

Answer:

your answer

don't forget to mark brainliest✌️✌️

7 0
3 years ago
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