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Stella [2.4K]
2 years ago
10

7. Perform the indicated operations: PLEASE HELP

Mathematics
1 answer:
Andrej [43]2 years ago
5 0
A. 5 5/8
b. 5/8
c. 31 1/4
d. 1 1/4
e. 10.38
f. 7.62
g. 19.04
h. 3.36134454
i. 21.899
j. 3.46
k. 0.08
l. 0.5
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Mumz [18]
The answer is 3: 3+5+8=5+8+3
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3 years ago
The mass of the sun is 2.13525×1030 kilograms. The mass of Mercury is 3.285×1023 kilograms. How many times greater is the mass o
Helga [31]
<span>6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.</span>
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3 years ago
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Trigonometry that’s due in one hour :(
expeople1 [14]

Answer:

(a)  \theta=\tan^{-1}(-0.890)

\implies \theta=-41.66908262 \pm 180 \textdegree n

\implies \theta=138.3309174..., 318.3309174...

\implies \theta=138\textdegree, 318\textdegree

(b)  \theta=\cos^{-1}\left(\dfrac{\sqrt{3} }{2}\right)

\implies \theta=30 \textdegree \pm360 \textdegree n, 330 \textdegree \pm360 \textdegree n

\implies \theta=30 \textdegree , 330 \textdegree

(c)  \theta=\sin^{-1}\left(\dfrac{1 }{2}\right)

\implies \theta=30 \textdegree \pm360 \textdegree n, 150 \textdegree \pm360 \textdegree n

\implies \theta=30 \textdegree , 150 \textdegree

3 0
2 years ago
189.271 in expanded form
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Answer:

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Step-by-step explanation: hope this helps <3

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3 years ago
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It takes Matt 3 minutes to read one page in a book. If he continues to read at the same pace, he can read 15 similar pages in mi
elena-14-01-66 [18.8K]

Answer:

a)45min

b)900min

Step-by-step explanation:

We were told that it takes Matt 3 minutes to read one page in a book.

It implies that 3minutes = 1page of the book

Then he continues to read at the same pace, he can read 15 similar pages in minutes.

a)Then, he can read 15 similar pages in

15x3 minutes.which is 45minutes.

b)Then if the book has 300 pages, it will take him. 300×3 minutes to read it.which is 900mins

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