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Stella [2.4K]
1 year ago
10

7. Perform the indicated operations: PLEASE HELP

Mathematics
1 answer:
Andrej [43]1 year ago
5 0
A. 5 5/8
b. 5/8
c. 31 1/4
d. 1 1/4
e. 10.38
f. 7.62
g. 19.04
h. 3.36134454
i. 21.899
j. 3.46
k. 0.08
l. 0.5
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X^4-64=0<br>The examples we did in class had solutions like "x=+-2" and "x=+-i(square root)3.​
hammer [34]

Answer:

Step-by-step explanation:

This isn't the same thing although you will get some factors that have i in them

(x^4 - 64) factors using the difference of squares.

(x^2 - 8)(x^2 + 8) Both of these factor using the difference of squares.

(x^2 - 8): factors into (x + sqrt(8) )(x - sqrt(8) )

(x^2 - 8):  factors further (x + 2*sqrt2)(x - 2sqrt(2)

(x ^2 + 8) : (x + sqrt(8)i ) (x - sqrt(8)i )

(x^2 + 8) : (x + 2sqrt(2)i) (x - 2sqrt(2)i)

Final answer

(x + 2*sqrt2)(x - 2sqrt(2)(x + 2*sqrt2)(x - 2sqrt(2)

3 0
3 years ago
I NEED MORE HELP! What is the slope-intercept equation for the following line.
professor190 [17]

Answer:

y=mx+c.................

7 0
2 years ago
Stuck on this question. May I please have some help?
Rina8888 [55]

Answer:

So a point is (-3,-5) and the vertex is (-4,-3)

Step-by-step explanation:

This is in vertex form. Vertex form is y=a(x-h)^2+k where (h,k) is the vertex.

The vertex here is (-4,-3)... now just use a value of x to plug in (any value besides -4)

I will choice -3.  This gives -2(-3+4)^2-3

f(-3)=-2(1)^2-3

f(-3)=-2-3

f(-3)=-5

So a point is (-3,-5) and the vertex is (-4,-3)

4 0
3 years ago
Read 2 more answers
Which relationship has a zero slope?
patriot [66]

Answer:

b has zero slop mark me as a brilliant

5 0
3 years ago
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At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperature is 50° Celsius. This
dybincka [34]

Answer:

D(t)=50(0.8)^t

Step-by-step explanation:

We are given that

Initially the difference between the cake's and the cooler's temperature ,a=50 degree Celsius

r=\frac{1}{5}/min

We have to find the function that gives the temperature difference in degrees Celsius D(t).

We know that

D(t)=a(1-r)^t

Substitute the values

D(t)=50(1-\frac{1}{5})^t=50(1-0.2)^t

D(t)=50(0.8)^t

This is required function that gives the temperature difference in degrees Celsius.

6 0
3 years ago
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