90.555555555555 repeating
Answer:
- 0.100
Step-by-step explanation:
Length of the ladder, H = 6 m
Distance at the bottom from the wall, B = 1.3 m
Let the distance of top of the ladder from the bottom at the wall is P
Thus,
from Pythagoras theorem,
B² + P² = H² .
or
B² + P² = 6² ..............(1) [Since length of the ladder remains constant]
at B = 1.3 m
1.3² + P² = 6²
or
P² = 36 - 1.69
or
P² = 34.31
or
P = 5.857
Now,
differentiating (1)

at t = 2 seconds
change in B = 0.3 × 2= 0.6 ft
Thus,
at 2 seconds
B = 1.3 + 0.6 = 1.9 m
therefore,
1.9² + P² = 6²
or
P = 5.69 m
on substituting the given values,
2(1.9)(0.3) + 2(5.69) ×
= 0
or
1.14 + 11.38 ×
= 0
or
11.38 ×
= - 1.14
or
= - 0.100
here, negative sign means that the velocity is in downward direction as upward is positive
Answer:
0.015
Step-by-step explanation:
0.15% = 0.0015
{transfer}
Working conditions in the United States in the early 1900’s can best be described as atrocious.
Answer:
a) A student travelling to school on public transport: 15/52 or 0.231
b) A student walking to school: 16/52 or 0.308
c) A student not cycling to school: 43/52 or 0.827
Step-by-step explanation:
Total people = 52
Travel Method Frequency
Public Transport 12
Car 15
Cycle 9
Walk 16
Find the relative frequency of.
The formula used will be: 
a) A student travelling to school on public transport:
Given Frequency: 12
Size of sample space: 52
Apply formula: 
Fraction = 12/52
Decimal = 0.231
b) A student walking to school
Given Frequency: 16
Size of sample space. 52
Apply formula: 
Fraction = 16/52
Decimal = 0.308
c) A student not cycling to school.
We will consider all students except those who cycle.
12+15+16 = 43
Given Frequency: 43
Size of sample space. 52
Apply formula: 
Fraction = 43/52
Decimal = 0.827