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Andrews [41]
2 years ago
13

A client is admitted with hypocalcemia. What are possible causes of hypocalcemia?

Biology
1 answer:
Vlada [557]2 years ago
4 0

Hypocalcemia can result from the following factors:

  • Lack of vitamin D or vitamin D resistance
  • post-surgery, hypoparathyroidism
  • due to autoimmune illness or hereditary causes of hypoparathyroidism
  • Inadequate vitamin D levels are brought on by renal disease or advanced liver disease.
  • Hypoparathyroidism, also known as pseudohypoparathyroidism
  • Parathyroid gland metastatic growth or heavy metal (copper, iron) invasion

Acute hypocalcemia is characterised by neuromuscular irritability. Cardiovascular symptoms of acute hypocalcemia are possible. Chronic hypocalcemia is frequently brought about by insufficient parathyroid hormone or vitamin D levels or by hormone resistance.

The right course of treatment depends on knowing the difference between acute and chronic hypocalcemia and between hypocalcemia with no symptoms and hypocalcemia with severe symptoms.

To learn more about hypocalcemia click here

brainly.com/question/14511652

#SPJ4

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What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow
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Answer:

<u> </u><u>The magnitude of the force exerted by the biceps </u>f_b_i_c_e_p_s<u> is 218.38N</u>

<u>The magnitude of the force exerted by the elbow </u>f_e_l_b_o_w<u> is 194.37N</u>

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps f_b_i_c_e_p_s -

Mass of the forearm=

m_f=1.50kg

Mass of the ball =

m_b_a_l_l=950g

   = 0.950kg

so, weight of the forearm=

w_f=m_f g

weight of the ball=

w_b_a_l_l=m_b_a_l_l g

Now , balancing torque about the elbow , we have-

F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36

F_b_i_c_e_p_s=218.38N

Now, lets calculate the force exerted by elbow F_e_l_b_o_w -

Balancing the vertical forces

F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l

F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)

F_e_l_b_o_w=194.37N

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