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pav-90 [236]
1 year ago
10

When a disease is rare in the general population, doctors are not likely to test everyone. Instead, they only test people that h

ave specific risk factors or show symptoms of the disease. Even if resources are available, why do you think doctors would avoid giving a test for a rare disease to everyone in the general population? Explain using ideas from probability that were explored in this project
Mathematics
1 answer:
rewona [7]1 year ago
7 0
Pleasee thanks thisss pleaseee :) thanks
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Lin and her brother each created a scale drawing of the backyard, but at different scales. Lin used a scale of 1 inch to 1 foot.
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Which equation has the same solution as 2x^2+16x-10=0
dmitriy555 [2]
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Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21
8 0
3 years ago
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Amélie runs a bakery. She wants to find out whether her cake sales are affected by the weather conditions. She recorded the dail
rodikova [14]

Answer:

the coeffiectans is 100

Step-by-step explanation:

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3 years ago
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Sheila bought some rose plants and sunflower plants.There were 35 rose plants than sunflower plants.If the ratio of the rose pla
DENIUS [597]
So assuming that youmeans there were 35 MORE rose plants than sunflower seeds, then

Rose:Sunflower =8:3

rose=sunflower+35
therefor

8 units=rose
3 units=sunflowers

rose-35=sunflower
8unit-35=3unit
5unit-35=0
5unit=35
therefor
35=5unit
divide by 5
7=1unit


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6 0
3 years ago
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
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