a fisherman travels 9mi downstream with the current in the same time he travels 3 mi upstream against the current. if the speed
of the current is 5mph what is the speed at which the fisherman travels in still water
1 answer:
Answer:
10 mph
Step-by-step explanation:
speed of boat in still water = x
speed of current = 5
speed of boat with current (downstream) = x + 5
speed of boat against current (upstream) = x - 5
distance downstream = 9
distance upstream = 3
time = t
speed = distance/time
distance = speed × time
downstream:
9 = (x + 5)t
upstream:
3 = (x - 5)t
9 = xt + 5t
3 = xt - 5t
9 = xt + 5t
-3 = -xt + 5t
-----------------
6 = 10t
t = 0.6
9 = (x + 5)0.6
15 = x + 5
x = 10
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It’s D I also trust the other guy
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A= 30ft, because you only have to multiply LxW= A that is equal to 2x15=30ft
Answer:
20
Step-by-step explanation:
25 + 7x = 165
25 + 7(20) = 165
25 + 140 = 165
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