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inysia [295]
2 years ago
10

If a neutral atom gains an electron, what is its charge?

Mathematics
1 answer:
DENIUS [597]2 years ago
7 0
C. Negative because since the neutral atom stands at 0 and positive ions are 1+ and electrons are negative if it gains the electron ( negative ) it will become negative.
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Between with pair of numbers is the exact product of 379 and 8
VikaD [51]

Answer:


Step-by-step explanation:

379 is a prime number.  Only 2 numbers will divide into it. 1 and 379

So you could do this

379 * 8 = 3032

(379 * 2  ) * 4 = 758 * 4 = 3032

(379 * 4 ) * 2 = 1516 * 2 = 3032


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3 years ago
If a line has a slope of 2 and contains the point (-2,1), what is its equation in point-slope form?
kondaur [170]
The equation for slope is y=mx+b. slope is m. 2 is the slope. so you know the m part of the equation is 2. just by eliminating the answers that don’t have 2 as the slope, A is your answer.
5 0
3 years ago
Find the next three terms of the geometric sequence -8, 12, -18,27
Pie

Answer:

-40.5, 60.75, -91.125

Step-by-step explanation:

first you want to find the common difference. So just divide 12 by -8, which is -1.5 and then multiply 27 by -1.5, which is -40.5 and continue two more times.

3 0
3 years ago
If you have 5 apples and u replace 3 how many apples do u have
attashe74 [19]

Answer:

2 I guess or what you mean with replace

Step-by-step explanation:

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4 0
2 years ago
Find the values of the sine, cosine, and tangent for ZA C A 36ft B <br> 24ft
Reptile [31]
<h2>Question:</h2>

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = \frac{\sqrt{13} }{2},  cos A = \frac{\sqrt{13} }{3},  tan A = \frac{2 }{3}

b. sin A = 3\frac{\sqrt{13} }{13},  cos A = 2\frac{\sqrt{13} }{13},  tan A = \frac{3}{2}

c. sin A = \frac{\sqrt{13} }{3},  cos A = \frac{\sqrt{13} }{2},  tan A = \frac{3}{2}

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Answer:</h2>

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Step-by-step explanation:</h2>

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

<em>i. First calculate the value of the missing side AB.</em>

<em>Using Pythagoras' theorem;</em>

⇒ (AB)² = (AC)² + (BC)²

<em>Substitute the values of AC and BC</em>

⇒ (AB)² = (36)² + (24)²

<em>Solve for AB</em>

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = \sqrt{1872}

⇒ AB = 12\sqrt{13} ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of 12\sqrt{13} ft (43.27ft).

<em>ii. Calculate the sine of ∠A (i.e sin A)</em>

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = \frac{opposite}{hypotenuse}             -------------(i)

<em>In this case,</em>

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (i) as follows;</em>

sin A = \frac{24}{12\sqrt{13} }

sin A = \frac{2}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

sin A = \frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

sin A = \frac{2\sqrt{13} }{13}

<em>iii. Calculate the cosine of ∠A (i.e cos A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = \frac{adjacent}{hypotenuse}             -------------(ii)

<em>In this case,</em>

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (ii) as follows;</em>

cos A = \frac{36}{12\sqrt{13} }

cos A = \frac{3}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

cos A = \frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

cos A = \frac{3\sqrt{13} }{13}

<em>iii. Calculate the tangent of ∠A (i.e tan A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = \frac{opposite}{adjacent}             -------------(iii)

<em>In this case,</em>

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

<em>Substitute these values into equation (iii) as follows;</em>

tan A = \frac{24}{36}

tan A = \frac{2}{3}

6 0
2 years ago
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