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harina [27]
2 years ago
13

Evacuate the following using suitable identities (102)^3

Mathematics
1 answer:
snow_lady [41]2 years ago
5 0

The value of (102)^3 exists 1061208.

<h3>How to estimate the value of (102)^3?</h3>

Let us rewrite (102)^3 as (100+2)^3

Now utilizing the identity (a+b)^3=a^3+b^3+3ab(a+b), we get

a = 100 and b = 2 then substitute the values of a and b then

(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]

= 1000000 + 8 + (600 × 102)

= 1000000 + 8 + 61200

= 1061208

Hence, (102)^3=1061208

Therefore, the value of (102)^3 exists 1061208.

To learn more about cubic polynomial equation refer to:

brainly.com/question/28181089

#SPJ9

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Step-by-step explanation:

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riadik2000 [5.3K]
<h3>Answer:</h3>

a) l = 5 + 2w

b) P = 2(l +w) = 2(5 +2w +w)

c) w = 8 cm, l = 21 cm

<h3>Explanation:</h3>

a) Using w for width, twice the width is 2w, and 5 more than that is 5+2w. This is your expression for l:

... l = 5 + 2w

b) The perimeter is the sum of the lengths of all sides, so is the sum of twice the length and twice the width.

... P = 2(l +w) = 2(5 +2w + w) . . . . substituting for l using the expression of (a)

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... 8 = w . . . . . . . . divide by 6

... l = 5 + 2·8 = 21 . . . . . find length using the formula for it

Dimensions are in centimeters, so we can write the solution as ...

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