Well we know these two angles are congruent, so we set their angles equal to each other.
5w - 69 = w + 3
4w = 72
w = 18
Now we plug w back into one of the equations, and then multiply whatever number we get by 2.
18 + 3 = 21
21 x 2 = 42
The measure of STU is 42°
Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer
Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
-2x - 6. -2x -6
0 = x^2 + 3x. Factor
0 = x (x + 3)
Solve: x = 0. x + 3 = 0. ——> x = -3. Substitute into one original equation to get y value for
y = 2x + 6.
y = 2(0) + 6. y = 2(-3) + 6
y = 6. y = -6 + 6 —-> y = 0
(0 , 6) And. (-3 , 0)
A/B is a reduced fraction which can be represented as a
terminating decimal if and only b is of the form 2^n5^n where m and n are non
negative integers. For example: 7/250, the terminating decimal here is 0.028 as
250 as the denominator equals to 2*5^2.
According to the above, we must know whether the denominator
have only 2-s and or 5-s as the prime factors. So,
Q = 8 = 2 ^3 = hence the denominator has only 2 prime
factors. Fraction P/Q will be termed as terminated decimal which is sufficient.
Answer:
(1, 0.25)
Step-by-step explanation:
To find when f(x)=g(x), then look for a value that is the same for both functions in the table. 0.25 occurs twice for the same x value. This is when they are equal. The solution is (1, 0.25).
<h3>
Explanation:</h3>
The first attachment is one way that quadrilaterals can be classified. If you've never studied a diagram like this before, it would certainly be mysterious.
There is a little more to it in that a "kite" is not the only kind of quadrilateral with no parallel sides.
Your diagram apparently doesn't recognize the special sorts of trapezoids you might have other than isosceles.
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The classifications on the first diagram are numbered. The numbers on the second diagram are the way I'd match up the descriptions to the bubbles in your diagram.