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harina [27]
2 years ago
13

Evacuate the following using suitable identities (102)^3

Mathematics
1 answer:
snow_lady [41]2 years ago
5 0

The value of (102)^3 exists 1061208.

<h3>How to estimate the value of (102)^3?</h3>

Let us rewrite (102)^3 as (100+2)^3

Now utilizing the identity (a+b)^3=a^3+b^3+3ab(a+b), we get

a = 100 and b = 2 then substitute the values of a and b then

(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]

= 1000000 + 8 + (600 × 102)

= 1000000 + 8 + 61200

= 1061208

Hence, (102)^3=1061208

Therefore, the value of (102)^3 exists 1061208.

To learn more about cubic polynomial equation refer to:

brainly.com/question/28181089

#SPJ9

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bija089 [108]

Answer:

-2.61803398875, -0.38196601125

or

(-3±√5)/2

Step-by-step explanation:

First, expand. (2x+3)² = 4x²+12x+9=5

4x²+12x+4 = 0

Quadratic equations take the form ax²+bx+c = 0

In this case,

a = 4

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You can solve with the equation x=(-b±√b²-4ac)/2a

Plug in:

(-12±√144-64)/8

(-12±√80)/8

(-12±√2^4×5)/8

(-12±4√5)/8

(-3±√5)/2

Final answer x = (-3±√5)/2

If you want decimal form: -2.61803398875, -0.38196601125

4 0
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After reading The Lord of the Rings, Francesca signs up for archery lessons. At her first lesson, she sets up her target 5 feet
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