The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2
=0
=>
=0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
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Danville,Keflavik,Somerville,Ulsan,,Smithfield
Answer:
C)
Step-by-step explanation:
If you divide 8:2 by two you get 4:1 which is the equivilant ratio.
Hope this helps.
Answer:
The probability is
≅ 
Step-by-step explanation:
Let's analyze the question.
There are 15 students in the 8th grade.
The students are randomly placed into three different algebra classes of 5 students each.
We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.
One possible way to solve this question is to think about the product probability rule.
We can use it because we are in an equiprobable space. (And also the events are independent).
Let's set for example a class for Evan.
The probability that Evan will be in a class is 
Then for Terry there are
places out of
that puts Terry in the Evan's class.
We write 
Finally for Trevor there are
places out of the remaining
that puts Trevor in the same class with Evan and Terry.
Using the product rule we write :

The probability of the event is
≅ 