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Dahasolnce [82]
3 years ago
14

Ben os travelling home to brimingham on the m1 and m42. both motorways have road works. He has a 50-50 chance of getting delay o

n the m42 and a 75% chance of being delayed on the M1.
what are the chances that he will not be delayed on his journey.
Mathematics
1 answer:
Contact [7]3 years ago
8 0
The answer is 1/8 or 12.5%
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ehidna [41]
Persia is the answer
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3 years ago
Y=2(x+1)^2 has how many real roots
oee [108]

The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

=> y = 2(x+1)^2

Take y=0 then,

=> 2(x+1)^2=0

=> (x+1)^2=0

=>(x+1)=0

=> x=-1

Hence the given equation has one real root and that is x=-1.

To learn more about real roots refer the below link

brainly.com/question/24147137

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1 year ago
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Help plzzzzzz 10 point question
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5 0
3 years ago
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Select the ratio equivalent to 8:2<br>A. 24:10 <br>B. 4:2<br>C.4:1<br>D. 32:12​
Mama L [17]

Answer:

C)

Step-by-step explanation:

If you divide 8:2 by two you get 4:1 which is the equivilant ratio.

Hope this helps.

4 0
3 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
4 years ago
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