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Ostrovityanka [42]
3 years ago
10

How to solve for s p=q+5+s

Mathematics
1 answer:
likoan [24]3 years ago
7 0
P=q+5+s
p-q=5+s
p-q-5=s
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Which line of best fit accurately represents the given scatter plot?
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The third one down
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Which of the following is an arithmetic sequence with common difference 2?
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D.

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Factor x^4 + xy^3 + x^3 + y^3. Hint, first factor a monomial. Please explain why!!!
almond37 [142]

Pull an x from the first two terms

x(x^3 + y^3) + (x^3 + y^3)   Now x^3 + y^3 is a common factor.

(x^3 + y^3)*(x + 1) That should be far enough. It can be factored further by factoring (x^3 + y^3) but there is no point because you can't do anything after that. But in case you want to know how x^3 + y^3 factors

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Part B

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3 0
3 years ago
Grades on a standardized test are known to have a mean of 1000 for students in the US. The test is administered to 453 randomly
Mademuasel [1]

Answer:

a:  1003 < µ < 1023

b:  See attached photo for answers

c:  see below

d and e:  See second attached photo

f:  See below

Step-by-step explanation:

a.  to find a confidence interval, first find the error with the formula,

E = Z(σ/√n)  where Z is the value of the z-score that relates to the confidence level, σ is the standard deviation of the population (or of the sample if the population standard deviation isn't given), and n is the sample size

For this problem, E = 1.96(108/√453) = 9.95 = 10

Now add and subtract that value form the sample average...

x - E < µ < x + E      becomes    1013 - 10 < µ 1013 + 10

simplifies to 1003 < µ < 1023

b.  See attached photo for hypothesis test results...

c.  H0:  µ = 1013  

    Ha:  µ > 1013 (claim)

They want to test if it's greater than their first attempt,  so this claim becomes the alternate hypothesis.  We're testing against their first attempt, that's why µ = 1013, not 1000

d and e.  See second attached photo for hypothesis test results...

f.  There is enough evidence to support the claim that the students second attempt was an improvement from their first attempt.  They happened to take a 2 hour tutoring course between tests.  This doesn't prove that the tutoring was effective thought.  It very well might have been effective, but also, the students taking the test again means they've already seen the test and know what to expect, which could have also boosted their scores.  

8 0
4 years ago
Okay hi
goblinko [34]

Answer:

30

Step-by-step explanation:

you have 5 marbles and 6 cards just multiply

Hope This Helps!     Have A Nice Day!!

8 0
3 years ago
Read 2 more answers
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