(2×10^15)/(4×10^9) = (2/4)×10^(15-9) = 0.5×10^6 = 5×10^5
The first number is 5×10^5 = 500,000 times larger than the second.
300 with a remainder of 10
3 0 0
1 4 | 4 2 1 0
4 2
1 0
Therefore, 4210 / 14 = 300 with a remainder of 10.
300 with a remainder of 10
This can be solved using a system of equations.
Subtract y from both sides.
Substitute:
Subtract 80 from both sides:
Divide both sides by 5:
Substitute.