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SVETLANKA909090 [29]
2 years ago
12

In which quadrants do solutions for the inequality y is less than or equal to two sevenths times x plus 1 exist? i, iii, and iv

i, ii, and iii i and iv all four quadrants
Mathematics
1 answer:
tigry1 [53]2 years ago
4 0

The solutions will lie  in all the four quadrants.

y≤2/7x+1

We have the following inequality:

y=2/7x+1

If x=0

y=2/7(0) +1

y=1

If y=0

x=-3.5

So the line passes through the points:

(0,1) and (-3.5,0)

To find the shaded region, let us take a point, namely, the origin and test it in the inequality:

y≤ 2/7x +1

0≤ 2/7(0) +1

0≤ 1 which is true

Since this is true, then the shaded region includes this point. This is shown below and as you can see the solutions exist in all four quadrants.

To learn more about Inequalities, visit brainly.com/question/12890742

#SPJ4

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Answer:

33 copies were paperback and 12 were hardcover.

Step-by-step explanation:

Let h represent the number of hardcover copies and p represent the number of paperback copies.

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h+p = 45

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Together we have the system

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We will use elimination to solve this.  First we will make the coefficients of the variable p the same; to do this, we will multiply the top equation by 5:

\left \{ {{5(h+p=45)} \atop {7h+5p=249}} \right. \\\\\left \{ {{5h+5p=225} \atop {7h+5p=249}} \right.

To eliminate p, we will subtract the equations:

\left \{ {{5h+5p=225} \atop {-(7h+5p=249)}} \right. \\\\-2h=-24

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Substitute this into our first equation:

12+p=45

Subtract 12 from each side:

12+p-12 = 45-12

p = 33

There were 33 paperback copies sold.

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