Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-8, -6)
Point (-3, -2)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute in points [Distance Formula]:
- [√Radical] (Parenthesis) Add:
- [√Radical] Evaluate exponents:
- [√Radical] Add:
- [√Radical] Evaluate:
- Round:
Answer:
Step-by-step explanation:
Answer:yes
Step-by-step explanation:
Answer:
x^2 | y^25 |√187x
Step-by-step explanation:
First you simplify the equation then you factor 184 into its prime factors which is 184 = 23 • 23
To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent. Factors which will be extracted are: 4 = 22 Factors which will remain inside the root are: 46 = 2 • 23 To complete this part of the simplification we take the square root of the factors which are to be extracted. We do this by dividing their exponents by 2: 2 = 2 At the end of this step the partly simplified SQRT looks like this: 2 • sqrt (46x5y50) Rules for simplifing variables which may be raised to a power: (1) variables with no exponent stay inside the radical (2) variables raised to power 1 or (-1) stay inside the radical (3) variables raised to an even exponent: Half the exponent taken out, nothing remains inside the radical. examples: (3.1) sqrt(x8)=x4 (3.2) sqrt(x-6)=x-3 (4) variables raised to an odd exponent which is >2 or <(-2) , examples: (4.1) sqrt(x5)=x2•sqrt(x) (4.2) sqrt(x-7)=x-3•sqrt(x-1) Applying these rules to our case we find out that SQRT(x5y50) = x2y25 • SQRT(x) sqrt (184x5y50) = 2 x2y25 • sqrt(46x)
pls brainlist
Answer: It depends on the terms.
Step-by-step explanation: In fraction terms 16 is equivalent to 4. In number terms 16 is a number larger than 4.
