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Minchanka [31]
2 years ago
13

At 570 mm hg and 25 c a gas sample has a volume of 2270 ml what is the final pressure at a volume of 1250 ml?

Chemistry
1 answer:
ValentinkaMS [17]2 years ago
3 0

Main Answer:

Given data:

Initial Pressure P1 = 570 mm hg

Initial Volume V1 = 2270 ml

Final Pressure P2 = ? mm hg

Final Volume V1 = 1250 ml

According to the ideal gas equation,

PV = constant.

P1V1 = P2V2

P2 = P1V1/V2

P2 = (570 x 2270) / 1250

P2 = 1035.12 mm hg

The final pressure at volume of 1250 ml is 1035.12 mm hg.

Explanation:

What is ideal gas equation ?

The ideal gas equation is as follows:

PV = nRT

where P = Pressure

V = Volume

n = number of moles of gas

R = Universal gas constant

T = Temperature

This ideal gas equation provides the macroscopic particles behavior of the gas. At this condition, the particles of the gas, won't be attract or repel each other. It is consider as the stable condition.

To know more about ideal gas equation, please visit:

brainly.com/question/21912477

#SPJ4

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3 years ago
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When the length of a chemical bond is short...
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Answer:

Option c. is correct

Explanation:

A chemical bond enables the formation of chemical compounds depending on the nature of the participating atoms like atoms, ions or molecules.

These are formed as a result of the force of attraction between oppositely charged ions.

It is formed by the overlapping of the atomic orbitals of the two atoms.

When the length of a chemical bond is short an electron is held tighter and the bond is stronger

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4 years ago
At constant temperature, when the volume of a gas is decreased, what happens to its pressure? Select one: a. It increases. b. It
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Answer:

The answer would be

a. it increases

3 0
4 years ago
Determine the final temperature of a system, if 120 grams had an initial temperature of 80°C and mixes with 3,000 g of water at
frutty [35]

Answer:

The final temperature of the mixture is 22.3°C

Explanation:

Assuming that the 120 g substance at 80°C is water, final temperature of the mixture can be determined using the formula:

Heat lost = Heat gained

Heat = mc∆T where m is mass, c is specific heat capacity of water, and ∆T is the temperature change =<em> Tfinal - Tinitial</em>.

Let the final temperature be T

Heat lost = 120 × c × (T - 80)

Heat gained = 3000 × c × ( T - 20)

Equating the heat lost and heat gained

120 × c × -(T - 80) = 3000 × c × (T - 20)

9600 - 120T = 3000T - 60000

60000 + 9600 = 3000T + 120T

69600 = 3120T

T = 69600/3120

T = 22.3°C

Therefore, the final temperature of the mixture is 22.3°C

4 0
3 years ago
Approximately how many ice cubes must melt to cool 650 milliliters of water from 29°C to 0°C? Assume that each ice cube contains
qwelly [4]

Answer : The number of ice cubes melt must be, 13

Explanation :

First we have to calculate the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

Density of water = 1.00 g/mL

Volume of water = 650 mL

\text{Mass of water}=1.00g/mL\times 650mL=650g

Now we have to calculate the heat released on cooling.

Heat released on cooling = m\times c\times (T_2-T_1)

where,

m = mass of water = 650 g

c = specific heat capacity of water = 4.18J/g^oC

T_2 = final temperature = 29^oC

T_2 = initial temperature = 0^oC

Now put all the given values in the above expression, we get:

Heat released on cooling = 650g\times 4.18J/g^oC\times (29-0)^oC

Heat released on cooling = 78793 J = 78.793 kJ   (1 J = 0.001 kJ)

As, 1 ice cube contains 1 mole of water.

The heat required for 1 ice cube to melt = 6.02 kJ

Now we have to calculate the number of ice cubes melted.

Number of ice cubes melted = \frac{\text{Total heat}}{\text{Heat for 1 ice cube}}

Number of ice cubes melted = \frac{78.793kJ}{6.02kJ}

Number of ice cubes melted = 13.1 ≈ 13

Therefore, the number of ice cubes melt must be, 13

3 0
4 years ago
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