Answer:
2.6 kJ
Explanation:
The formula for the amount of heat (q) absorbed by the water is
q = mCΔT
1. Calculate ΔT
ΔT = 23.5 °C - 22.1 °C = 1.4 °C
2. Calculate q
q₂ = mCΔT = 500 g × 4.184 J·°C⁻¹g⁻¹ × 1.4 °C = 2900 J = 2.9 kJ
Answer:
21.28 grams solute can be added if the temperature is increased to 30.0°C.
Explanation:
Solubility of solute at 20°C = 32.2 g/100 grams of water
Solute soluble in 1 gram of water = 
Mass of solute in soluble in 56.0 grams of water:

Solubility of solute at 30°C = 70.2g/100 grams of water
Solute soluble in 1 gram of water = 
Mass of solute in soluble in 56.0 grams of water:

If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C
Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g
Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g
Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:
39.312 g - 18.032 g = 21.28 g
21.28 grams solute can be added if the temperature is increased to 30.0°C.
Composed of molecules formed by atoms of two or more different elements.
<span>Answer: option C. Refrigerant. When the fluid vaporizes(passes from liquid to vapor) absorbs a lot of energy (called latent vaporization heat) which causes that the surroindings cool. The latent vaporization heat of the fluid permits the refrigeration process and the fluid is the refrigerant, this is the substance that permit that the refrigeration process take place.</span>