Answer:
- The graph of the function is attached below.
- The x-intercepts will be: (2, 0), (-2, 0)
- The y-intercept will be: (-20, 0)
Explanation:
Given the function
As we know that the x-intercept(s) can be obtained by setting the value y=0
so
switching sides
Add 20 to both sides
Dividing both sides by 5
so the x-intercepts will be: (2, 0), (-2, 0)
we also know that the y-intercept(s) can obtained by setting the value x=0
so
so the y-intercept will be: (-20, 0)
From the attached figure, all the intercepts are labeled.
Answer:
import java.util.Scanner;
public class num8 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter month's budget");
double monthBudget = in.nextDouble();
double totalExpenses = 0.0;
double n;
do{
System.out.println("Enter expenses Enter zero to stop");
n = in.nextDouble();
totalExpenses += n;
}while(n>0);
System.out.println("Total expenses is "+totalExpenses);
System.out.println("The amount over your budget is "+ Math.abs(monthBudget-totalExpenses));
}
}
Explanation:
- Using Java programming language
- Prompt user for month's budget
- Use Scanner class to receive and store the amount entered in a variable
- Use a do while loop to continuously request user to enter amount of expenses
- Use a variable totalExpenses to add up all the expenses inside the do while loop
- Terminate the loop when user enters 0 as amount.
- Subtract totalExpenses from monthBudget and display the difference as the amount over the budget
Answer:
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
H(X)=5.4224 bits per symb
H(X|Y="not C")=0.54902 bits per symb
Explanation:
P(B)=2P(C)
P(A)=2P(B)
But
P(A)+P(B)+P(C)=1
4P(C)+2P(C)+P(C)=1
P(C)=1/7
Then
P(A)=4/7
P(B)=2/7
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
iii
If X={A,B,C}
and P(Xi)={4/7,2/7,1/7}
where Id =logarithm to base 2
Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}
=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}
=5.4224 bits per symb
if P(C) =0
P(A)=2P(B)
P(B)=1/3
P(A)=2/3
H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)
=0.54902 bits per symb
Answer:
IBM Automatic Sequence Controlled Calculator (ASCC)
