Answer:
The correct answer is -
A) 35 g
B)30 mL
C)1.66666666666667g/ml3
Explanation:
Given:
mass of graduated cylinder containing 40 mL = 60 g
volume of water = 40 ml
increase in the level of water = 70 ml
increase in mass = 95
Solution:
A) mass of object -
increased mass - initial mass
90 - 60 = 35 g
B) volume of object
increased volume - initial volume
70 - 40 = 30 mL
C) density d=m/v
d=35/30
d=1.66666666666667
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