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Burka [1]
2 years ago
13

A scientist samples a population of butterflies and finds that 56% are heterozygous at a particular locus. If the population is

in hardy-weinberg equilibrium, what should be the frequency of the homozygous individuals in this population?.
Biology
1 answer:
d1i1m1o1n [39]2 years ago
4 0

0.44  the frequency of the homozygous individuals in this population.

What is Hardy-Weinberg principle ?

The Hardy-Weinberg equilibrium is a principle stating that the genetic variation in a population will remain constant from one generation to the next in the absence of disturbing factors.

From the Hardy Weinberg Law of Population and Genetics,

We have

x²+2xy+y²=1 and

x+y=1

where

x = frequency of the dominant allele in the population

y = frequency of the recessive allele in the population

x2 = percentage of homozygous dominant individuals

y2 = percentage of homozygous recessive individuals

2xy = percentage of heterozygous individuals

Given 2xy = 0.56

from here, y=0.28/x, (the frequency of the recessive allele ) can be obtained

we need to find 'x'

recall, x+y=1, x=1-y

substituting this gives us

y=0.28/(1-y), which becomes,

y(1-y)=0.28

y²- y + 0.28 (quadratic equation)

Solving this to find 'y' gives two imaginary values of y = 0.44 but ,

There is no imaginary solution  .

Learn more about Hardy Weinberg Law of Population

brainly.com/question/14669053

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