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Elena-2011 [213]
2 years ago
10

Travis was attempting to make muffins to take to a neighbor that had just moved in down the street. The recipe that he was worki

ng with required ¾ cup of sugar and ⅛ cup of butter.
Travis accidentally put a whole cup of butter in the mix.
What is the ratio of sugar to butter in the original recipe? What amount of sugar does Travis need to put into the mix to have the same ratio of sugar to butter that the original recipe calls for?
If Travis wants to keep the ratios the same as they are in the original recipe, how will the amounts of all the other ingredients for this new mixture compare to the amounts for a single batch of muffins?
The original recipe called for ⅜ cup of blueberries. What is the ratio of blueberries to butter in the recipe? How many cups of blueberries are needed in the new enlarged mixture?
This got Travis wondering how he could remedy similar mistakes if he were to dump in a single cup of some of the other ingredients. Assume he wants to keep the ratios the same.

How many cups of sugar are needed if a single cup of blueberries is used in the mix?
How many cups of butter are needed if a single cup of sugar is used in the mix?
How many cups of blueberries are needed for each cup of sugar?
Mathematics
1 answer:
aev [14]2 years ago
4 0
A. The recipe required 3/4 cup of sugar and 1/8 cup of butter.
The ratio of the sugar to butter in the original recipe is

B. If Travis accidentally put a whole cup of butter in the mix, then he needs to put
cup of sugar.
C. Travis has to put 1/8 cup of butter, but he put 1 cup of butter. The ratio is

If Travis wants to keep the ratios the same as they are in the original recipe, he needs to put 8 times more of all the other ingredients.
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The circumference of Dion's bicycle tire is 56.52 inches. What is the diameter of Dion's bicycle tire? (Use 3.14 for i.)​
Dafna1 [17]

Answer:

<h2>The answer is 18 inches</h2>

Step-by-step explanation:

Circumference of a circle = πd

where

d is the diameter of the circle

From the question

Circumference = 56.52 inches

π = 3.14

To find the diameter substitute the value of the circumstance into the above formula and solve for the diameter

That's

56.52 = πd

d =  \frac{56.52}{\pi}  \\ d =  \frac{56.52}{3.14}

We have the final answer as

<h3>d = 18 inches</h3>

Hope this helps you

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3 years ago
Which form of payment can Courtney lose and not get back?
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3 years ago
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Read the caption! Thanks, if you can helps thank you
Kamila [148]

Step-by-step explanation:

For a triangle, any 2 side lengths of the triangle must be greatee than the 3rd side.

Given a triangle with side lengths 11, 23 and x,

we have:

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(06.04 MC)
Andru [333]

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

◉ \large\bm{ -4}

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

Before performing any calculation it's good to recall a few properties of integrals:

\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx +  \int_{a}^bmdx}

\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a  f(x)dx= \int^c _a f(x)dx+  \int^{b} _c  f(x)dx }

So we apply the first property in the first expression given by the question:

\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}

And we solve the second integral:

\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx  = 2 \int ^3_{-2} f(x)dx +   2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }

Then we take the last equation and we subtract 10 from both sides:

\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx  = 8}

And we divide both sides by 2:

\small\longrightarrow \sf{\dfrac{2  {  \int}^{3} _{2}  }{2}  =  \dfrac{8}{2} }

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}

Then we apply the second property to this integral:

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}

Then we use the other equality in the question and we get:

\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx  =  2 \int ^3_{-2} f(x)dx  = 8 +  2 \int ^3_{-2} f(x)dx  = 4}

\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}

We substract 8 from both sides:

\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}

• \small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}

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Schach [20]
Q= 14 and 1/3 (fourteen and one third)

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