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Nonamiya [84]
2 years ago
5

Solve. plz hep------ ;3

Mathematics
1 answer:
Schach [20]2 years ago
6 0
Q= 14 and 1/3 (fourteen and one third)

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skelet666 [1.2K]

Answer:

0.6 pages per hour

8 0
3 years ago
What does .3 equal to this a really easy question of a 4th grader?
MA_775_DIABLO [31]
0.3 is equal to 3/10 or 30%
6 0
3 years ago
Read 2 more answers
Which values from the set {−6,−4,−3,−1,0,2} satisfy this inequality?
Vladimir [108]
-12x+3 greater than or equal to 5
-12x greater than or equal to to 2
To turn the negative sign of -12x into positive, we multiply both sides by minus, which shifts the inequality sign.
So, 12x less than or equal to 2
x is less than or equal to 1/6
Therefore, 0, -1, -3, -4 and -6 satisfy this inequality.
3 0
3 years ago
I think I need to find x
ozzi

Answer:

-6

Step-by-step explanation:

the x value is just plugging that number in for x so

-3x-8=10 (add 8 to both sides) so

-3x=18 (divide by -3 on both sides) so

x=-6

7 0
3 years ago
Read 2 more answers
A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

5 0
2 years ago
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