Im confuse gusy can u help me?
2 answers:
Answer:
11. 333... which can also be written as 11 1/3.
Step-by-step explanation:
Sure.
√(6c - 4) = 8
Squaring both sides:
6c - 4 = 64
6c = 64 + 4 = 68
c = 68/6
= 11. 333...
Answer:
![c=\dfrac{34}{3}](https://tex.z-dn.net/?f=c%3D%5Cdfrac%7B34%7D%7B3%7D)
Step-by-step explanation:
<u>Given equation</u>:
![\sqrt{6c-4}=8](https://tex.z-dn.net/?f=%5Csqrt%7B6c-4%7D%3D8)
Square both sides:
![\implies (\sqrt{6c-4})^2=8^2](https://tex.z-dn.net/?f=%5Cimplies%20%28%5Csqrt%7B6c-4%7D%29%5E2%3D8%5E2)
![\implies 6c-4=64](https://tex.z-dn.net/?f=%5Cimplies%206c-4%3D64)
Add 4 to both sides:
![\implies 6c-4+4=64+4](https://tex.z-dn.net/?f=%5Cimplies%206c-4%2B4%3D64%2B4)
![\implies 6c=68](https://tex.z-dn.net/?f=%5Cimplies%206c%3D68)
Divide both sides by 6:
![\implies \dfrac{6c}{6}=\dfrac{68}{6}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B6c%7D%7B6%7D%3D%5Cdfrac%7B68%7D%7B6%7D)
![\implies c=\dfrac{34}{3}](https://tex.z-dn.net/?f=%5Cimplies%20c%3D%5Cdfrac%7B34%7D%7B3%7D)
<u>Verify the solution</u> by inputting the found value of c back into the equation:
![\implies \sqrt{6\left(\dfrac{34}{3}\right)-4}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%7B6%5Cleft%28%5Cdfrac%7B34%7D%7B3%7D%5Cright%29-4%7D)
![\implies \sqrt{\dfrac{204}{3}-4}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%7B%5Cdfrac%7B204%7D%7B3%7D-4%7D)
![\implies \sqrt{68-4}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%7B68-4%7D)
![\implies \sqrt{64}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%7B64%7D)
![\implies \pm 8](https://tex.z-dn.net/?f=%5Cimplies%20%5Cpm%208)
Therefore, the solution of the found value of c is verified.
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Answer:
Step-by-step explanation:
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