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3 years ago

Match the graph with the correct equation.

Mathematics

1 answer:

konstantin123 [22]3 years ago

7 0

Look like B to me

It cant be C which has a negative slope.

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an elevator can carry 800 of weight. A football player weighting 280 pounds gets on the elevator with a student. Write and solve

Nesterboy [21]

Answer:

$425\geq x$

425 pounds or less can be added after the student and football player.

Step-by-step explanation:

let x = remaining weight

(note that >/= is greater than or equal to.)

800 - 280 - 95 >/= x

425 >/= x

8 0

3 years ago

3 3/4 -1 3/14 in simpilist form

lakkis [162]

For this case we must simplify the following expression:

$3 \frac {3} {4} -1 \frac {3} {14} =$

To do this, we convert the mixed numbers to improper fractions:

$\frac {4 * 3 + 3} {4} - \frac {14 * 1 + 3} {14} =\\\frac {15} {4} - \frac {17} {14} =\\\frac {14 * 15-4 * 17} {4 * 14} =\\\frac {210-68} {56} =\\\frac {142} {56} =\\\frac {71} {28} =\\2 \frac {15} {28}$

Answer:

$\frac {71} {28} = 2 \frac {15} {28}$

6 0

3 years ago

A pound of grapes costs $2.49. Lucas bought two pounds of grapes. He gave the clerk a $10.00 bill. How much change did Lucas get

GaryK [48]

Answer:

$5.02

Step-by-step explanation:

$2.49 × 2 = $4.98

$10 - $4.98 = $5.02

7 0

2 years ago

Please Help, I can't figure out this problem

Otrada [13]

Answer:

<h2>The answer is 5 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question

The points are (9,-7) and (5, -4)

The distance between them is

$d = \sqrt{ ({9 - 5})^{2} + ({ - 7 + 4})^{2} } \\ = \sqrt{ {4}^{2} + ({ - 3})^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25}$

We have the final answer as

<h3>5 units</h3>

Hope this helps you

3 0

3 years ago

SCALCET8 3.9.026.MI. A trough is 10 ft long and its ends have the shape of isosceles triangles that are 5 ft across at the top a

kherson [118]

Answer:

The answer is "0.624"

Step-by-step explanation:

$b = 5x\\\\h = x\\\\ l = 10 \\$

Using formula:

$V = (\frac{1}{2})(b)(h)(l) \\\\$

$= \frac{1}{2} \times (5x)\times (x) \times (10)\\\\= 5x\times x \times 5\\\\= 25x^2$

$\frac{dV}{dt} = 50x \ \frac{dx}{dt} \\\\\text{(where x represents the height in feet and}\ \frac{dv}{dt} = 13\ \frac{ft^3}{min})\\\\\frac{dx}{dt} = (\frac{1}{50})(\frac{1}{x}) \ \frac{dV}{dt}\\\\$

When the water is 5 inches deep then:

$x = (\frac{5}{12})\ ft\\\\13 =50(\frac{5}{12}) \ \frac{dx}{dt}\\\\13 \times 12 =50(5) \ \frac{dx}{dt}\\\\\frac{13 \times 12}{50 \times 5} = \frac{dx}{dt}\\\\\frac{156}{250} = \frac{dx}{dt}\\\\ \frac{dx}{dt}= 0.624$

5 0

3 years ago