Answer:
x = 3 units
SV = 2 units
Step-by-step explanation:
In
QR and ST are chords such that:
QR = ST = 4
That is both the chords are equal in measure.
Equal chords are at equal distance from the center of the circle. Therefore,
VZ = UZ
4x - 6 = 6
4x = 6 + 6
4x = 12
x = 12/4
x = 3 units
Since, perpendicular dropped from the center of the circle bisects the chord.
Answer:
how long will it take for what
Step-by-step explanation:
Answer:
Step-by-step explanation:
In the given figure, secants PA and PC are intersecting outside of the circle at point P.
PA = PB + AB = 7 + 5 = 12
PC = 14, PD =?
By the property of intersecting secants outside of a circle:
Answer:
AD = 104
Step-by-step explanation:
Since is the perpendicular bisector of AD, then
DB = AB, that is
9x - 2 = 7x + 10 ( subtract 7x from both sides )
2x - 2 = 10 ( add 2 to both sides )
2x = 12 ( divide both sides by 2 )
x = 6
Thus
AD = 7x + 10 + 9x - 2 = 16x + 8 ← substitute x = 6
AD = 16(6) + 8 = 96 + 8 = 104
