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2 years ago

The data set below has a lower quartile of 13 and an upper quartile of 37.

Mathematics

1 answer:

timama [110]2 years ago

6 0

The correct option regarding the outliers of the data-set is given by:

The greatest value, 78, is the only outlier.

<h3>How to use the quartiles of a data-set to identitfy outliers?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.

The first quartile is the median of the first half of the data-set.

The third quartile is the median of the second half of the data-set.

The interquartile range is the difference of the third quartile with the first quartile.

Measures that are more than 1.5 IQR from Q1 and Q3 are considered outliers.

The IQR for this problem is:

IQR = 37 - 13 = 24.

Hence the bounds for outliers are:

Less than 13 - 1.5 x 24 = -23.

Greater than 37 + 1.5 x 24 = 73,

The options are:

No outliers.

Only 1 is an outlier.

Only 78 is an outlier.

Both 1 and 78 are outliers.

Hence the correct option is that only 78 is an outlier.

More can be learned about outliers of a data-set at brainly.com/question/17083142

#SPJ1

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qaws [65]

We can use this problem:

Isabella has 4 videogames and she has played 2/7 of them so far. So, how much of the video games has she played?

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1 year ago

The length of the top of a computer desk is 2 1/4 feet longer than it’s width. If it’s width measures y feet, express its length

Lera25 [3.4K]

Answer:

The length as an algebraic expression in y is $y + (2\frac{1}{4} )$ ft

Step-by-step explanation:

The measure of the width of the computer desk = y feet

The measure of the length of the desk = width + 2 1/4 ft

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Hence, the length as an algebraic expression in y is $y + (2\frac{1}{4} )$ ft

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4 years ago

Divide (5x + 6x^3 - 8) ÷(x - 2) PLEASE HELP DUE IN 5 MINUTES

Leya [2.2K]

Answer:

6x^2+12x+29+50/x-2

Step-by-step explanation:

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3 years ago

List x1, x2, x3, x4 where xi is the left endpoint of the four equal intervals used to estimate the area under the curve of f(x)

n200080 [17]

Answer:

Option A. 4, 4.5, 5, 5.5

Step-by-step explanation:

Left point: a=x=4

Right point: b=x=6

Range: r=b-a→r=6-4→r=2

Width of each of the four equal intervals: w=2/4→w=0.5

The first left endpoint is x1=a→x1=4

The second left endpoint is x2=x1+w→x2=4+0.5→x2=4.5

The third left endpoint is x3=x2+w→x3=4.5+0.5→x3=5

The fourth left endpoint is x4=x3+w→x4=5+0.5→x4=5.5

Then, the list is: x1, x2, x3, x4 = 4, 4.5, 5, 5.5

4 0

3 years ago

An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can

serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0 ......[1]

the solution for the equation is given by:

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

On comparing the given equation with [1] we have;

a = -16 ,b = 80 and c = 300

then;

$t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}$

$t= \frac{-80\pm \sqrt{6400+19200}}{-32}$

$t= \frac{-80\pm \sqrt{25600}}{-32}$

Simplify:

$t = -\frac{5}{2}$ = -2.5 sec and $t = \frac{15}{2}$ = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0

3 years ago