Answer:
k=10
Step-by-step explanation:
g(x)=2x^2+ kx+18
when x=-2
g(-2)=2 (-2)^2 -2k +18
Since when x is -2, y =6
6=2 (-2)^2 -2k +18
6=18+8-2k
2k=26-6
2k=20
k=10
Answer:
4 quizzes are taken per week
9514 1404 393
Answer:
5 hours
Step-by-step explanation:
The volume of the pool is ...
V = LWH
V = (10 ft)(8 ft)(5 ft) = 400 ft^3
At the given fill rate, the time it will take is ...
(400 ft^3)/(80 ft^3/h) = 5 h
It will take 5 hours for the pump to fill the pool.
Part a)
Answer: 5*sqrt(2pi)/pi
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Work Shown:
r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi
Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"
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Part b)
Answer: 3*sqrt(3pi)/pi
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Work Shown:
r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi
Note: the same issue comes up as before in part a)
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Part c)
Answer: sqrt(19pi)/pi
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Work Shown:
r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi
5x-5=4x+10
x=15
75-5=70
180-70=110
6y-4=110
6y=114
y=19