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Alika [10]
1 year ago
14

The data set below has a lower quartile of 13 and an upper quartile of 37.

Mathematics
1 answer:
timama [110]1 year ago
6 0

The correct option regarding the outliers of the data-set is given by:

The greatest value, 78, is the only outlier.

<h3>How to use the quartiles of a data-set to identitfy outliers?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference of the third quartile with the first quartile.
  • Measures that are more than 1.5 IQR from Q1 and Q3 are considered outliers.

The IQR for this problem is:

IQR = 37 - 13 = 24.

Hence the bounds for outliers are:

  • Less than 13 - 1.5 x 24 = -23.
  • Greater than 37 + 1.5 x 24 = 73,

The options are:

  • No outliers.
  • Only 1 is an outlier.
  • Only 78 is an outlier.
  • Both 1 and 78 are outliers.

Hence the correct option is that only 78 is an outlier.

More can be learned about outliers of a data-set at brainly.com/question/17083142

#SPJ1

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Answer:

k=10

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g(-2)=2 (-2)^2 -2k +18

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6=2 (-2)^2 -2k +18

6=18+8-2k

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3 years ago
A water pump fills a swimming pool at a rate of 80
Nat2105 [25]

9514 1404 393

Answer:

  5 hours

Step-by-step explanation:

The volume of the pool is ...

  V = LWH

  V = (10 ft)(8 ft)(5 ft) = 400 ft^3

At the given fill rate, the time it will take is ...

  (400 ft^3)/(80 ft^3/h) = 5 h

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2 years ago
Read 2 more answers
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svetoff [14.1K]
Part a)

Answer: 5*sqrt(2pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi

Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"

============================================================

Part b)

Answer: 3*sqrt(3pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi

Note: the same issue comes up as before in part a)

============================================================

Part c)

Answer: sqrt(19pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi
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2 years ago
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LUCKY_DIMON [66]
5x-5=4x+10
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75-5=70
180-70=110
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