The data set below has a lower quartile of 13 and an upper quartile of 37.
1 answer:
The correct option regarding the outliers of the data-set is given by:
The greatest value, 78 , is the only outlier .
<h3>How to use the quartiles of a data-set to identitfy outliers?</h3>
The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile. The first quartile is the median of the first half of the data-set. The third quartile is the median of the second half of the data-set. The interquartile range is the difference of the third quartile with the first quartile. Measures that are more than 1.5 IQR from Q1 and Q3 are considered outliers .
The IQR for this problem is:
IQR = 37 - 13 = 24.
Hence the bounds for outliers are:
Less than 13 - 1.5 x 24 = -23. Greater than 37 + 1.5 x 24 = 73,
The options are:
Both 1 and 78 are outliers.
Hence the correct option is that only 78 is an outlier.
More can be learned about outliers of a data-set at brainly.com/question/17083142
#SPJ1
You might be interested in
The answer is 375..........
Answer:
18
Step-by-step explanation:
y=mx + b
m is the slope.
Therefore, 18 should be the slope
Answer:
6647 is a whole. For you to know the relationship between the 6s in this number write their values. The value of the first 6 is 6000. The value of the second 6 is 600.
Answer:
1
Step-by-step explanation:
1+1+1+1+11+1+1+1+11+1×0+1
30×0+1, Anything multiplied by 0 is 0
0+1
1
Answer:
thx
Step-by-step explanation: