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Pepsi [2]
3 years ago
15

Two identical masses are moving down a slope one masses traveling twice as fast as the other mass how does the kinetic energy of

one mass compared to the other
Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Answer:

One mass's kinetic energy is 4 times the other.

Step-by-step explanation:

The formula for kinetic energy is KE=\frac{1}{2}mv^2

Where

KE is the kinetic energy

m is the mass

v is the velocity

  • Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
  • Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v

<u>KE of 1st mass is:</u>

\frac{1}{2}mv^2

<u />

<u>KE of 2nd mass is:</u>

\frac{1}{2}m(2v)^2\\=\frac{1}{2}m(4v^2)\\=\frac{1}{2}mv^2 * 4

Hence, the kinetic energy of the 2nd mass is 4 times the first.

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An incomplete distribution is given below:Variable You are given that the median value is 70 and the total number of items is 20
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Answer:

The missing frequencies are x = 8 and y = 43.

Step-by-step explanation:

Median Value =70

Then the median Class =60-80

Let the missing frequencies be x and y.

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\left|\begin{array}{c|ccccccc}Value&0-20&20-40&40-60&60-80&80-100&100-120&120-140\\Frequency&12&30&x&66&y&27&14\\$Cumu.Freq&12&42&42+x&108+x&108+x+y&135+x+y&149+x+y\end{array}\right|

From the table

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Cumulative Frequency before the median class, f=42+x

Class Width, h=10

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70 = 60+ \dfrac{100- 42+x }{66}\times 10\\70 = 60+ \dfrac{58+x }{66}\times 10\\70-60=\dfrac{58+x }{66}\times 10\\10*66=10(58+x)\\58+x=66\\x=66-58\\x=8

200=149+x+y

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y=43

Hence, the missing frequencies are x = 8 and y = 43.

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