One of them is 3,8,3,8 and the other is 4,6,4,6
Answer:
The missing frequencies are x = 8 and y = 43.
Step-by-step explanation:
Median Value =70
Then the median Class =60-80
Let the missing frequencies be x and y.
Given: Total Frequncy = 200 , Median = 46

From the table
Here, n = 200
n/2 = 100
Lower Class Boundary of the median class, l=60
Frequency of the median class(f) =66
Cumulative Frequency before the median class, f=42+x
Class Width, h=10


200=149+x+y
200=149+8+y
y=200-(149+8)
y=43
Hence, the missing frequencies are x = 8 and y = 43.
The height of the shed, h, is 12.5.
lwh = 1500
(12) x (10) x h = 1500
120 x h = 1500
(120 x h)/120 = 1500/120
h = 12.5
Hope this helps!