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3 years ago

15

Two identical masses are moving down a slope one masses traveling twice as fast as the other mass how does the kinetic energy of

one mass compared to the other

1 answer:

GaryK [48]3 years ago

6 0

Answer:

One mass's kinetic energy is 4 times the other.

Step-by-step explanation:

The formula for kinetic energy is $KE=\frac{1}{2}mv^2$

Where

KE is the kinetic energy

m is the mass

v is the velocity

Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v

<u>KE of 1st mass is:</u>

$\frac{1}{2}mv^2$

<u />

<u>KE of 2nd mass is:</u>

$\frac{1}{2}m(2v)^2\\=\frac{1}{2}m(4v^2)\\=\frac{1}{2}mv^2 * 4$

Hence, the kinetic energy of the 2nd mass is 4 times the first.

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