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Pepsi [2]
3 years ago
15

Two identical masses are moving down a slope one masses traveling twice as fast as the other mass how does the kinetic energy of

one mass compared to the other
Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Answer:

One mass's kinetic energy is 4 times the other.

Step-by-step explanation:

The formula for kinetic energy is KE=\frac{1}{2}mv^2

Where

KE is the kinetic energy

m is the mass

v is the velocity

  • Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
  • Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v

<u>KE of 1st mass is:</u>

\frac{1}{2}mv^2

<u />

<u>KE of 2nd mass is:</u>

\frac{1}{2}m(2v)^2\\=\frac{1}{2}m(4v^2)\\=\frac{1}{2}mv^2 * 4

Hence, the kinetic energy of the 2nd mass is 4 times the first.

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A patient is to take 4 2/3 tablespoons of medicine per day in 4 equally divided doses. How much medicine is to be taken in each
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Answer:

1 1/6

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3 years ago
Select the correct answer from each drop-down menu.
olganol [36]

The system of inequalities is:

y ≤ -0.05*x^2 + 6x

y >  1.5x + 45

(30, 90) is not a solution of that system, while (60, 160) is a solution.

<h3>How to get the system of inequalities?</h3>

We know that the revenue y is given by:

y ≤ -0.05x^2 + 6x

And we know that the costs are 1.5x + 45, and the revenue must be larger than that, so we also have the inequality:

y >  1.5x + 45

So the system is:

y ≤ -0.05*x^2 + 6x

y >  1.5x + 45

Now, the point (30, 90) means that we need to replace x by 30 and y by 90, replacing that in the second inequality, we will get:

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For the second point we do the same: x= 60, y = 160, replacing that in the second inequality we get:

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160 ≤  -0.05*60^2 + 6*60 = 180

This is also true.

So the point (60, 160) is a solution to the system.

If you want to learn more about systems of inequalities, you can read:

brainly.com/question/9774970

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When statements p="two linear functions have different coefficients of x" and q="the graphs of two functions intersect at exactly one point", then the statement q \Rightarrow p have a form: "If the graphs of two functions intersect at exactly one point, then two linear functions have different coefficients of x."



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