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Aleonysh [2.5K]
1 year ago
14

Si al invertir $60.000 se pierde un 8% ¿A cuánto asciende la pérdida?

Mathematics
1 answer:
svetoff [14.1K]1 year ago
6 0

Trabajando con porcentajes, concluimos que la pérdida es de $4800.

<h3>¿A cuánto asciende la pérdida?</h3>

Sabemos que la inversión inicial es de $60000, y de esta cantidad, se pierde un 8%.

Entonces la pérdida va a ser el 8% de $60000.

Podemos escribir las relaciones:

$60000 = 100%

x = 8%

Queremos resolver esto para x, tomando el cociente entre esas relaciones y resolviendo para x obtenemos:

x = $60000*(8%/100%) = $60000*0.08 = $4800

Así, concluimos que la pérdida es de $4800.

Sí quieres aprender más sobre porcentages:

brainly.com/question/843074

#SPJ1

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Step-by-step explanation:

If it is proportional that means the y value divided by the x value will give you a constant slope.

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2/5 = 0.4

so you could write the equation y= 0.4x  where x is the number of pound.

Part A:     y= 0.4(1)    

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Part B.    (10,4) in this case it will means that for 10 pounds of cabbage it will cost $4.

   Plot it into the equation and find out

 in the coordinates (10,4) 4 is the y and 10 is the x

   4= 0.4(10)

  4= 4  

Which means it true that 10 pounds of cabbage will cost 4 dollars.

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(2/5)^-2(-3)^4<br><br> What is the equivalent?
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and second term

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Sophie [7]

Answer:

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