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s344n2d4d5 [400]
3 years ago
14

How to resolve this equation1/5(x-8)= x-16

Mathematics
1 answer:
Mashcka [7]3 years ago
3 0
1/5 (x - 8) = x - 16...distribute thru the parenthesis
1/5x - 8/5 = x - 16 ...multiply everything by common denominator of 5
x - 8 = 5x - 80 ...subtract 5x from both sides
x - 5x - 8 = - 80 ...add 8 to both sides
x - 5x = -80 + 8 ...combine like terms
-4x = - 72 ...divide both sides by -4
x = -72/-4
x = 18
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What is the value of p in the question below. 10x9/2x4= px 5
ycow [4]

Answer:

p = 5

Step-by-step explanation:

We have that:

\frac{x^{a}}{x^{b}} = x^{a-b}

So

\frac{x^{9}}{x^{4}} = x^{9-4} = x^{5}

10/2 = 5

Then

\frac{10x^{9}}{2x^{4}} = 5x^{9-4} = 5x^{5}

Finding p:

5x^{5} = px^{5}

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Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

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3 years ago
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