Question

Find the length of the radius of a circle with a center at –7 2i and a point on the circle at 33 11i.

Answer 1

The length of the radius of a circle exists 41 units.

How to estimate the length of  the radius of a circle?

Given: The center exists at -7+2i and a point in the circle at 33+11i.

The radius of the circle exists given by the following formula;

The radius of the circle $=\sqrt{x^{2}+y^{2}}$

The center exists at -7 + 2i and a point in the circle at 33 + 11i.

$&x(33-(-7)), y(2 \mathrm{i}-11 \mathrm{i})$

simplifying the equation, we get

$&\mathrm{x}(33+7), \mathrm{y}(-9 \mathrm{i})$

$&\mathrm{x}(40), \mathrm{y}(-9(-1))$

$&\mathrm{x}(33+7), \mathrm{y}(9)$

The center of the circle exists at $&\mathrm{x}(33+7), \mathrm{y}(9)$.

The length of the radius of a circle exists,

Radius $}=\sqrt{x^{2}+y^{2}}$

substituting the values of x and y, we get

Radius$}=\sqrt{40^{2}+9^{2}}$

Radius $}=\sqrt{1600+81}$

Radius $=\sqrt{1681}$

Radius = 41 unit

Therefore, the length of the radius of a circle exists 41 unit.

To learn more about length of the radius of a circle refer to:

brainly.com/question/10443107

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