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abruzzese [7]
4 years ago
15

I’ll give brainliest to the correct answer !

Mathematics
1 answer:
Klio2033 [76]4 years ago
8 0

I think that the answers are A and C. I may not be right so you may want to double check. Wish I could have been more help.


Good Luck! Hope I helped:)

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Given the vertices of ∆ABC are A (2,5), B (4,6) and C (3,1), find the vertices following each of the transformations FROM THE OR
djyliett [7]
The answer

a) the main rule for transformations <span>Rx-axis is as following
 original (x, y) --------------- the final coordinates become  (x, -y)

so the answer is  </span><span>A' (2, -5), B' (4,-6) and C' (3,-1)

b) just put the figure of y= 3, and check the value after projection

it is </span> A' (2, 1), B' (4,0) and C' (3,4)

c) <span>T<-2,5>, the main rule is as following

T(a, b) ----- applying on (x, y) is  (a+x, b+y) for the transformed points

in our case, </span><span>A' (0,10), B' (2,11) and C' (1,6)

d) the same method as above for </span><span>d. T<3,-6>, we found
</span><span>A '(5,-1), B '(7,0) and C ' (6,-5)


</span>
3 0
3 years ago
Simplify -2(-4x + 5)
Bingel [31]

Answer:

the answer would be 8x-10

3 0
3 years ago
Twelve less than the quotient of a number and 8 is -1
Setler [38]

Twelve less than the quotient of a number and 8 is -1

(n ÷ 8) - 12 = -1


8 0
3 years ago
Need assistance with the question attached
natulia [17]

Answer:

x = \frac{4\pi }{9},\frac{10\pi }{9}

Step-by-step explanation:

Given equation is,

\sqrt{3}\text{tan}(\frac{2x}{3})+1=0

By solving this equation,

\text{tan}(\frac{2x}{3})=-\frac{1}{\sqrt{3}}

x=\frac{2}{3}\times \text{tan}^{-1}(-\frac{1}{\sqrt{3}}) [tangent of any angle is negative in IInd and IVth quadrants]

x = \frac{2}{3}\times (\frac{2\pi }{3}), \frac{2}{3}\times (\frac{5\pi}{3})

x = \frac{4\pi }{9},\frac{10\pi }{9}

Therefore, value of x in the interval of [0, 2π] are \frac{4\pi }{9},\frac{10\pi }{9}.

6 0
3 years ago
(Q4) Solver the inequality.<br> 6^x &lt; 3^x
IgorLugansk [536]

Answer:

D

Step-by-step explanation:

We need to graph both  6^x  and  3^x  and figure out <em>the x-value at which the graph of  6^x is LESS THAN that of the graph of 3^x.</em>

<em />

The attached picture shows the graph of  6^x in BLUE and the graph of  3^x in RED.

<em><u>We need to find x-value where the BLUE graph is "BELOW" the RED graph.</u></em> We can see that this occurs when x < 0.

Thus the correct answer is  D

4 0
4 years ago
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