The answer
a) the main rule for transformations <span>Rx-axis is as following
original (x, y) --------------- the final coordinates become (x, -y)
so the answer is </span><span>A' (2, -5), B' (4,-6) and C' (3,-1)
b) just put the figure of y= 3, and check the value after projection
it is </span> A' (2, 1), B' (4,0) and C' (3,4)
c) <span>T<-2,5>, the main rule is as following
T(a, b) ----- applying on (x, y) is (a+x, b+y) for the transformed points
in our case, </span><span>A' (0,10), B' (2,11) and C' (1,6)
d) the same method as above for </span><span>d. T<3,-6>, we found
</span><span>A '(5,-1), B '(7,0) and C ' (6,-5)
</span>
Answer:
the answer would be 8x-10
Twelve less than the quotient of a number and 8 is -1
(n ÷ 8) - 12 = -1
Answer:
x = 
Step-by-step explanation:
Given equation is,

By solving this equation,
[tangent of any angle is negative in IInd and IVth quadrants]
x =
,
x = 
Therefore, value of x in the interval of [0, 2π] are
.
Answer:
D
Step-by-step explanation:
We need to graph both
and
and figure out <em>the x-value at which the graph of
is LESS THAN that of the graph of
.</em>
<em />
The attached picture shows the graph of
in BLUE and the graph of
in RED.
<em><u>We need to find x-value where the BLUE graph is "BELOW" the RED graph.</u></em> We can see that this occurs when x < 0.
Thus the correct answer is D