Question

Rodrigo knows that AM←→⊥MN←→−and UK←→⊥MN←→−.

Answer 1

Answer:

$\overleftrightarrow{AL} \parallel \overleftrightarrow{UK} \ \ \huge \checkmark$

$m\angle MBK=90^{\circ }\ \huge \checkmark$

Step-by-step explanation:

We are given :

$\overleftrightarrow{AM} \perp \overleftrightarrow{MN}$

and

$\overleftrightarrow{UK} \perp \overleftrightarrow{MN}$

………………………………………………

The lines AM and UK are perpendicular to the same line MN.

Then

$\overleftrightarrow{AM} \parallel \overleftrightarrow{UK}$

We also have :

$\overleftrightarrow{AM} = \overleftrightarrow{AL}$

Therefore ,

$\overleftrightarrow{AL} \parallel \overleftrightarrow{UK}$

………………………………………………………

∠MBK and ∠UBN are two vertically opposite angles.

Then

m∠MBK = m∠UBN

Since , m∠UBN = 90°

Then

m∠MBK = 90°