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Aleksandr-060686 [28]
2 years ago
7

Write a system of equations to describe the situation below, solve using elimination, and fill in

Mathematics
1 answer:
Andrej [43]2 years ago
6 0

Answer:  Child is $1 and Adult is $3, per person.

Step-by-step explanation:

We have two unknowns, so we need at least two equations.  Let C and A stand for the price of a ticket for a child and an adult, respectively.

The income for Monday and Tuesday can be calculated:

Monday:   16C + 42A = $142

Tuesday:  24C + 26A = $102

Rearrange the second equation to isolate one of the variables.  I'll pick C:

24C + 26A = $102

C  = ($102 - 26A)/24

Now use this expression for C in the first equation

16C + 42A = $142

16(($102 - 26A)/24) + 42A = $142

16(($102 - 26A)/24) + 42A = $142

(1632 - 416A)/24 + 42A = $142

(68 - 17.3333A + 42A = $142

24.6667A = 74

A = 3  [The price of an adult pool admission is $3]

Use this value in either equation to find the price of a child's admission:

24C + 26A = $102

24C + 26*($3) = $102

24C = 102 - 78

C = $1   [The price of a child's admission to the pool is $1]

Check to see if these prices satisfy both equations:

Monday:   16C + 42A = $142

Tuesday:  24C + 26A = $102

---

Monday:   16*(1) + 42*(3)  = $142   ?   YES

Tuesday:  24*(1) + 26*(3) = $102   ?    YES

<u>Child is $1 and Adult is $3, per person.</u>

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The complete factor of the expression \rm 8x^5 + 2x^4 + 4x^2 is \rm 2x^{2} (4x^3 + x^2 + 2 )correct option is D.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The expression is \rm 8x^5 + 2x^4 + 4x^2.

To solve the expression properly we have to take common (2x²). Then we have

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Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
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As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

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