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nlexa [21]
3 years ago
9

Dr. Sandoval, a farm veterinarian, just weighed a particular pig and found out it is 96 kilograms. The last time she checked, th

e pig weighed 100 kilograms. What percent lighter is the pig now?
Mathematics
1 answer:
slega [8]3 years ago
4 0
4% because 100=100% -4 =96
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Brian says that the expression 8n + 2 is equal to 83 when n=1. Explain why Brian’s answer is incorrect?
GalinKa [24]

Answer:

8n+2 first let’s plug in n which is 1

8(1)+2=10

The answer is 10 but Brian said the expression is equal to 83. He is incorrect because 8 times 1 is 8 and then plus 2 is 10.

I hope it helps.

5 0
2 years ago
Please solve the following question
Hoochie [10]

Question 1:

A = w * l

A = 5432m^2

l = 97

A / l = w

5432 / 97 = 56

w = 56

Question 2:

Perimeter of rectangle = 2w + 2l

P = 336

w = 79

P - 2w = 2l

336 - 158 = 178

178 / 2 = 89

l = 89

8 0
3 years ago
Rationalise the denominator of:<br>1/(√3 + √5 - √2)​
Paul [167]

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given expression is

\rm :\longmapsto\:\dfrac{1}{ \sqrt{3}  +  \sqrt{5}  -  \sqrt{2} }

can be re-arranged as

\rm :\longmapsto\:\dfrac{1}{ \sqrt{3}   -   \sqrt{2}   +  \sqrt{5} }

\rm \:  =  \: \dfrac{1}{( \sqrt{3}  -  \sqrt{2} ) +  \sqrt{5} }

On rationalizing the denominator, we get

\rm \:  =  \: \dfrac{1}{( \sqrt{3}  -  \sqrt{2} ) +  \sqrt{5} }  \times \dfrac{( \sqrt{3}  -  \sqrt{2} ) -  \sqrt{5} }{( \sqrt{3}  -  \sqrt{2} ) -  \sqrt{5} }

We know,

\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}

So, using this, we get

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{ {( \sqrt{3}  -  \sqrt{2} )}^{2}  -  {( \sqrt{5}) }^{2} }

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{3 + 2 - 2 \sqrt{6}   - 5}

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{5 - 2 \sqrt{6}   - 5}

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{ - 2 \sqrt{6}}

\rm \:  =  \: \dfrac{ - ( -  \sqrt{3} +  \sqrt{2}  + \sqrt{5}) }{ - 2 \sqrt{6}}

\rm \:  =  \: \dfrac{-  \sqrt{3} +  \sqrt{2}  + \sqrt{5}}{2 \sqrt{6}}

On rationalizing the denominator, we get

\rm \:  =  \: \dfrac{-  \sqrt{3} +  \sqrt{2}  + \sqrt{5}}{2 \sqrt{6}}  \times \dfrac{ \sqrt{6} }{ \sqrt{6} }

\rm \:  =  \: \dfrac{-  \sqrt{18} +  \sqrt{12}  + \sqrt{30}}{2  \times 6}

\rm \:  =  \: \dfrac{-  \sqrt{3 \times 3 \times 2} +  \sqrt{2 \times 2 \times 3}  + \sqrt{30}}{12}

\rm \:  =  \: \dfrac{-  3\sqrt{2} + 2 \sqrt{3}   + \sqrt{30}}{12}

Hence,

\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3}  +  \sqrt{5}  -  \sqrt{2} } =\dfrac{-  \sqrt{3 \times 3 \times 2} +  \sqrt{2 \times 2 \times 3}  + \sqrt{30}}{12}}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h3><u>More Identities to </u><u>know:</u></h3>

\purple{\boxed{\tt{  {(x  -  y)}^{2} =  {x}^{2} - 2xy +  {y}^{2}}}}

\purple{\boxed{\tt{  {(x   +   y)}^{2} =  {x}^{2} + 2xy +  {y}^{2}}}}

\purple{\boxed{\tt{  {(x   +   y)}^{3} =  {x}^{3} + 3xy(x + y) +  {y}^{3}}}}

\purple{\boxed{\tt{  {(x - y)}^{3} =  {x}^{3} - 3xy(x  -  y) -  {y}^{3}}}}

\pink{\boxed{\tt{  {(x + y)}^{2} +  {(x - y)}^{2} = 2( {x}^{2} +  {y}^{2})}}}

\pink{\boxed{\tt{  {(x + y)}^{2}  -  {(x - y)}^{2} = 4xy}}}

6 0
3 years ago
The perimeter of the rectangle is 28 units.
Reika [66]

Answer:

since we can't see the image, I'm just giving it a try

if it's wrong, it's fine for you to delete it

(see below)

Step-by-step explanation:

if one of the length is 5.6 units then the other will be 5 units

if one of the length is 4 units then the other will be 7 units

if one of the length is 2 units then the other will be 14 units

if one of the length is 1.86666666667 units then the other will be 15 units

if you're looking of an area, it might be 7 units

and I think that's all I've got

(hope it helps)

3 0
3 years ago
Reduce into lowest terms
Pavel [41]

Answer:

4/6 = 2/3

10/12 = 5/6

18/24 = 3/4

7 0
2 years ago
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