3 years ago

Help me please!! I don’t understand please help it’s due today

Mathematics

2 answers:

Arisa [49]3 years ago

7 0

Answer:

Step-by-step explanation:

MrMuchimi3 years ago

3 0

Point a (-7,-1)
point b (5,-1)
point c (8,4)
(x,y) format

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70 - q - q - 2q = 80???

Aneli [31]

70-q-q-2q= 80

combine like terms first

so you get 70-4q= 80

subtract 70 on both sides and you get -4q= 10

divide -4 on both sides and you get q= 10/-4 or -2.5

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Find the value of k if the distance between (2,k) and (6,7) is 4√2 unit

andreyandreev [35.5K]

Answer:

k = 3

Step-by-step explanation:

We have the distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ . We can plug in $4\sqrt{2}$ = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

$4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\$

$(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2$

$32 = (4)^2 + (7-k)^2$

$32 = 16 + (7-k)^2$

$32 - 16 = (7-k)^2$

$16 = (7-k)^2$

$\sqrt{16} = (7-k)$

$4 = 7-k$

$k = 3$

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3 years ago