Question

Sloane kicked a soccer ball off the ground at a speed of 48 feet per second. The height of the ball can be represented by the function H(t) = −16t2 + 48t, where t is the time in seconds. How many seconds did the ball travel before returning the ground?

Answer 1

If the speed of the ball after kicking is 48 feet per second then the ball will return on the ground after 3 seconds.

Given that the speed of the ball after kicking is 48 feet per second and the function that represents the height of the ball is $-16t^{2} +48t$.

We are required to find the time that the ball took to travel before returning the ground.

We know that speed is the distance a thing covers in a particular time period.

The height of the ball after t seconds is as follows:

h(t)=$-16t^{2} +48t$

It is at ground at the instants of t.

Hence,

$-16t^{2} +48t$=0

-16t(t-3)=0

We want value of t different of 0, hence :

t-3=0

t=3.

Hence if the speed of the ball after kicking is 48 feet per second then the ball will return on the ground after 3 seconds.

Learn more about speed at brainly.com/question/4931057

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