Ask question

Ask question

All categories

3 years ago

15

The graph shown below expresses a radical function that can be written in the form f(x) = a * (x + k) ^ (1 / n) + c does the gra

ph tell you about the value of k in this function ? A. k equals zero.
B. k is less than zero.
C. k is greater than zero.
D. It is not possible to tell whether k is greater than or less than zero.

2 answers:

Allisa [31]3 years ago

5 0

Answer: For me it is the answer is the a I do not know if my answer will help you

Nataly [62]3 years ago

3 0

Answer is d hope this helps

You might be interested in

Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

3 years ago

Which statement describes the definition of a function?

Tom [10]

Answer:

an activity or purpose natural to or intended for a person or thing.

Step-by-step explanation:

: >

3 0

3 years ago

Read 2 more answers

PLS HELP ASAP FEJKRKJGR My bad dont mind the blue bubble

kondor19780726 [428]

Answer:

10

Step-by-step explanation:

yellow

6+6+3=15

so

for green

4+4+2=10

8 0

3 years ago

Read 2 more answers

If the surface area of a cube is 384, what is the length of one of the sides of<br> the cube?

Setler79 [48]

Answer:

S = 8

Each side of a face is 8 units.

Step-by-step explanation:

The surface area of the cube is 384 units.

One face of the cube has an area of s^2

A cube has 6 faces

6s^2 = 384 Divide by 6

s^2 = 384 / 6

s^2 = 64 Take the square root of both sides

sqrt(s^2) = sqrt(64)

s = 8

6 0

3 years ago

Read 2 more answers

592 rounded to nearest hundred

GaryK [48]

Answer:

600

Step-by-step explanation:

Because 592 is closer to 600 than it is to 500, you would round UP to 600.

7 0

3 years ago

Read 2 more answers