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Bogdan [553]
2 years ago
13

Graduate management aptitude test (gmat) scores are widely used by graduate schools of business as an entrance requirement. supp

ose that in one particular year, the mean score for the gmat was 473, with a standard deviation of 104. what values are three standard deviations within the mean?
Mathematics
1 answer:
klemol [59]2 years ago
7 0

The values that exist two standard deviations above and below the mean are 681 and 265.

<h3>How to determine the values?</h3>

The given parameters exist:

Mean = 473

Standard deviation =104

The values above and below the mean exist calculated utilizing:

$x=\bar{x} \pm n \sigma$

In this case n = 2.

So, we have, $x=\bar{x} \pm 2 \sigma$

The value above is:

x = 473 + 2 * 104 = 681

The value below is:

x = 473 - 2 * 104 = 265

Therefore, the values that exist two standard deviations above and below the mean are 681 and 265.

To learn more about standard deviation refer to:

brainly.com/question/937592

#SPJ4

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It will be $105 a month
5 0
3 years ago
Mark buys a wooden board that is 7 1/2 feet long. The cost of the board is $0.50 per foot, including tax. What is the total cost
artcher [175]

Answer:

Total cost of Mark's board is $3.75.

Step-by-step explanation:

We are given the following in the question:

Length of wooden board =

=7\dfrac{1}{2}\text{ foot}

Unit cost of board = $0.50 per foot

Total cost of board =

=\text{Length of board}\times \text{Unit cost of board}\\\\=7\dfrac{1}{2}\times 0.50\\\\=\dfrac{15}{2}\times \dfrac{1}{2}\\\\=\dfrac{15}{4} = 3.75\$

Thus, total cost of Mark's board is $3.75.

7 0
3 years ago
t^2+4t+4 t^2-2t+1 Consider the parametric curve a. Find points on the parametric curve where the tangent lines are vertical. b.
kondaur [170]

Answer:

a) t = 1, b)  t = -2, c) Concave upward: (-\infty, 1). No intervals being concave downward.

Step-by-step explanation:

a) Tangent line is vertical if slope is undefined, whose points are associated with discontinuities of the function. Rational functions have discontinuities associated with the denominator:

f(t) = \frac{t^{2}+4\cdot t +4}{t^{2}-2\cdot t + 1}

By factorizing each component, the function is re-arranged as:

f(t) = \frac{(t+2)^{2}}{(t-1)^{2}}

There is no avoidable discontinuities. The only point where tangent line is vertical is t = 1.

b) Tangent line is horizontal if slope is equal to zero, whose point is associated to the points that makes function equal to zero. Rational functions have horizontal tangent lines if numerator is equal to zero and denominator is different to zero. Hence, the only point where tangent line is  horizontal is t = -2.

c) An interval is concave upward if exist an absolute minimum inside, which can be found by the help of the First and Second Derivative Tests.

f'(t) = \frac{2\cdot (t+2)\cdot (t-1)^{2}-2\cdot (t-1)\cdot (t+2)^{2}}{(t-1)^{4}}

f'(t) = 2\cdot (t+2)\cdot (t-1)\cdot \left[\frac{t-1-t-2}{(t-1)^{4}}\right]

f'(t) = -\frac{6\cdot (t+2)\cdot (t-1)}{(t-1)^{4}}

f'(t) = -\frac{6\cdot (t+2)}{(t-1)^{3}}

The only critical point is:

-6\cdot (t+2) = 0

t = -2 (which coincides with the result of point b)

f''(t) = -6\cdot \left[\frac{(t-1)^{3}-3\cdot (t-1)^{2}\cdot (t+2)}{(t-1)^{6}}\right]

f''(t) = -6\cdot \left[\frac{1}{(t-1)^{3}}-\frac{3\cdot (t+2)}{(t-1)^{4}}  \right]

The value associated with the critical point is:

f''(-2) = \frac{2}{9}

Which means that critical point is an absolute minimum, and, consequently, the interval that is concave upward is (-\infty, 1). There is no absolute maximums and, therefore, there is no interval that is concave downward.

7 0
4 years ago
Evaluate the given algebraic expression for x = 2 and y = 3.
Aneli [31]

Answer:

C

Step-by-step explanation:

To evaluate substitute x = 2 and y = 3 into the expression

- 3xy = - 3 × 2 × 3 = - 6 × 3 = - 18 → C

4 0
4 years ago
2. Carlos is installing new carpet in his house. He estimates that he can install 20
nata0808 [166]
A. 20 Carlos can install in one hour
8 0
3 years ago
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