Plsssssssssssssss help with 11

Find the total travel time depart 5:30 pm mountain standard time arrive 9:30 pm central time

daser333 [38]

Answer:

5 hours

Step-by-step explanation:

I hope this helps

5 0

3 years ago

Cheyenne is making a recipe that uses 5 cups of beans and 2 cups of carrots wich combination below uses the same ratio of beans

amid [387]

Answer:

5/2

Step-by-step explanation:

4 0

3 years ago

An equation is given. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places w

Rina8888 [55]

Answer:

a) The general solution θ = nπ±π/6

The all solutions are - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b) The solutions in the interval [ 0,2π)

θ = - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

Step-by-step explanation:

Step( i):-

Given an equation 2 cos (2θ)-1 =0

2 cos (2θ) = 1

cos(2θ) = 1/2

cos(2θ) = cos (π/3)

Step(ii):-

a)

The general solution of cos θ = cos ∝ is given by

θ = 2nπ±∝

The general solution of cos(2θ) = cos (π/3) is

2θ = 2nπ±π/3

θ = nπ±π/6

Put n=0 θ = ±π/6

Put n =1 θ = π±π/6

θ = π-π/6 = 5π/6

θ = π+π/6 = 7π/6

put n =2

θ = 2π±π/6

θ = 2π-π/6 = 11π/6

θ = 2π+π/6 = 13π/6

The all solutions are - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b)

The solutions in the interval [ 0,2π)

θ = - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

Final answer:-

a)

The all solutions are - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b)

The solutions in the interval [ 0,2π)

θ = - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

8 0

3 years ago

How would I graph this?

vladimir2022 [97]

The difference between the two equations is the + 3. This means the vertex of the parabola will move 3 units to the left at the point (-3, 0)

7 0

3 years ago

Use the tangent identity to

Lunna [17]

Answer:

$tan(x)=\frac{44\sqrt{89}}{89}$

Step-by-step explanation:

tan is defined as: $tan(x)=\frac{opposite}{adjacent}$

sin is defined as: $sin(x)=\frac{opposite}{hypotenuse}$

cos is defined as: $cos(x)=\frac{adjacent}{hypotenuse}$

We can also define tan as: $tan(x)=\frac{sin(x)}{cos(x)}$

because plugging in the definitions of sin and cos in we get: $tan(x)=\frac{(\frac{opposite}{hypotenuse})}{(\frac{adjacent}{hypotenuse})}\\\\tan(x)=\frac{opposite}{hypotenuse}*\frac{hypotenuse}{adjacent}\\\\tan(x)=\frac{opposite}{adjacent}$

which you'll notice is the original definition of tan(x)

So using this definition of tan(x) we can use the givens sin(x) and cos(x) to find tan(x)

$sin(x)=\frac{44}{45}\\\\cos(x)=\frac{\sqrt{89}}{45}\\\\tan(x)=\frac{sin(x)}{cos(x)}$

plugging in sin(x) and cos(x) we get:

$tan(x)=\frac{\frac{44}{45}}{\frac{\sqrt{89}}{45}}\\\\tan(x)=\frac{44}{45}*\frac{45}{\sqrt{89}}\\\\tan(x)=\frac{44}{\sqrt{89}}$

We usually don't like square roots in the denominator, and from here we want to rationalize the denominator which we do by removing the square root from the denominator.

We can do this by multiplying the fraction by: $\frac{\sqrt{89}}{\sqrt{89}}$ which doesn't change the value of the fraction since it simplifies to 1, but it gets rid of the square root in the denominator

$tan(x)=\frac{44}{\sqrt{89}}*\frac{\sqrt{89}}{\sqrt{89}}\\\\tan(x)=\frac{44\sqrt{89}}{89}$

5 0

9 months ago