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siniylev [52]
2 years ago
8

Given f(x)=abx+c. How would increasing the value of a change the graph?

Mathematics
1 answer:
Margaret [11]2 years ago
6 0

Increasing the value of a increases the initial value of our exponential, and also increases the rate of growth of the function.

<h3>How would increasing the value of a change the graph?</h3>

Y assume we have an exponential equation of the form:

y = a*b^x + c

In this case, a is what we know as the "initial value" of the exponential.

Notice that when we evaluate in x = 0, we get:

y = a*b^0 + c

y = a + c

So increasing a will increase the initial value of what we are representing, but it will also increase the "rate" at which our function increases when x increases.

if you want to learn more about exponential functions:

brainly.com/question/11464095

#SPJ1

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Nadia has 5 different types of fruits in her fridge. She wants to choose one or two types of fruit
Arturiano [62]
5 fruit juices because she has five different fruits.
7 0
4 years ago
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What is the sum of the solutions of the equation 1.5x^2 - 2.5x -1.5 = 0? Round to the nearest hundredth. ​
BARSIC [14]

Answer:

Sum = 1.67

Step-by-step explanation:

Given:

1.5x^2 - 2.5x -1.5 = 0

Required

Determine the sum of the solutions

This question will be answered using quadratic formula:

x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where:

a = 1.5

b = -2.5

c = -1.5

So, we have:

x = \frac{-(-2.5)\±\sqrt{(-2.5)^2 - 4*1.5*-1.5}}{2*1.5}

x = \frac{2.5\±\sqrt{6.25 +9}}{3}

x = \frac{2.5\±\sqrt{15.25}}{3}

x = \frac{2.5\±3.91}{3}

x = \frac{2.5+3.91}{3} or x = \frac{2.5-3.91}{3}

The sum of the solution is then calculated as:

Sum = \frac{2.5+3.91}{3} + \frac{2.5-3.91}{3}

Take L.C.M

Sum = \frac{2.5+3.91+2.5-3.91}{3}

Sum = \frac{5}{3}

Sum = 1.67

5 0
3 years ago
Can someone please explain why x= -2! ASAP!!
bearhunter [10]
Because you add both negative x’s which is -2 and add the -6 in the right side so then it’s -2x=4
Divide and you get x=-2
6 0
3 years ago
Read 2 more answers
Need help with finding foci of parabola
mixer [17]
Hello,
Please, see the attached files.
Thanks.

7 0
3 years ago
Please show me how to do this problem
sleet_krkn [62]

Answer:

Hi there, you can use Pitagoras relationship to solve this up (Without using any other "tool".

Point A is located wheter in (-6,8) or could be located in (-6,8)

Step-by-step explanation:

Point A is 10 units away from the origin, and its x coordinate is -6, using this information, you can draw a triangle  from 0 to -6 (the basis) and using 10 as the hypotenuse, so, you have this equation:

H^{2} = x^{2} +y^{2}

solving for Y variable, you have this

y=±\sqrt{10^{2}-(-6)^{2}  }

Note the combined sing ±, meaning that y=8 is a valid answer and that y= -8 is also a valid answer.

Hope It helps

5 0
3 years ago
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