Answer:
Angle BPQ = 64°
Step-by-step explanation:
4x + 12 +2x = 90
6x + 12 = 90
- 12 -12
6x = 78
x = 13°
BPQ = ((4(13) + 12)°
(52 + 12)°
64°
Answer:
Square root of 4 is 2
so 1+
=4
frac{[1+sqrt{2x-1]}^2 }{4}=3
so 1+sqrt{2x-1]}^2=12
so 1+sqrt{2x-1}=V12
sqrt{2x-1}=V12-1
2x-1=(V12-1)^2=12-2V12+1=13-2V12
2x=13+1-2V12
2x=14-2V12
x=7-V12
x=7-2V3
I put an attachment to explain better
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
Use the slope formula -
(9-7)/(6-3)= 2/3
y=2/3x+b
plug point in to get b
7=2/3(3) + b
7=2+b
5=b
y=2/3x+5
It is given in the question that QS bisects angle PQR .

And since, QS bisects angle PQR, therefore
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Substituting the values of angle PQS and angle RQS, we will get

PQR is twice of angle PQS. Therefore angle PQR is
